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Rufina [12.5K]
1 year ago
14

How do you find out if a like is parallel, perpendicular, or coincidental when theres 2 equations

Mathematics
1 answer:
finlep [7]1 year ago
8 0

The slope intercept form of the equation of a line is given as:

y = mx + c

where m = the slope of the line

c = the y - intercept of the line

1) Two line are parallel if they have the same slope

That is:

\begin{gathered} \text{If the equation for line 1 is: y = m}_1x+c_1 \\ \text{If the equation for line 2 is:  y = m}_2x+c_2 \\ \text{Then, line 1 is parallel to line 2 if m}_1=m_2 \end{gathered}

2) Two equations are perpendicular if the slope of one is the negative inverse of the other.

\text{That is : m}_1=\text{ }\frac{-1}{m_2}

3) Two equations are coincidental if they have the same slope and the same y intercept

\begin{gathered} \text{That is: m}_1=m_2_{} \\ \text{and c}_1=c_2 \end{gathered}

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someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your
Lunna [17]

Answer:

Part A) The area of the figure is 24\ units^{2}

Part B) The perimeter of the figure is 20\ units

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

A=\frac{1}{2}bh

<u>Area of triangle ABD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(9-5)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

<u>Area of triangle BCD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(5-1)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of the figure is

12\ units^{2}+12\ units^{2}=24\ units^{2}

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+AD

we have

A(-5,1),B(-8,5),C(-5,9),D(-2,5)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units

Find the distance BC

d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units

Find the distance CD

d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units

Find the distance AD

d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units

substitute the values

P=5+5+5+5=20\ units

7 0
3 years ago
9.7q = 9.1q - 7.92<br> q =
AleksAgata [21]

Answer:

q = -13.2

Step-by-step explanation:

9.7q = 9.1q - 7.92

Subtract 9.1q from both sides.

0.6q = -7.92

Divide both sides by 0.6

q = -13.2

Double check your work.

9.7(-13.2) = 9.1(-13.2) - 7.92

-128.04 = -120.12 - 7.92

-128.04 = -128.04

5 0
3 years ago
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