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Keith_Richards [23]
2 years ago
13

How many pizzas can u but if they cost $14 and u have $60

Mathematics
2 answers:
ozzi2 years ago
7 0
You can buy 4 pizzas because if you divide 60 by 14 you will get 4.28...
Round it and you will get 4.
kow [346]2 years ago
3 0

you can buy 4 pizzas

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Ixl help ASAP PLZ HELP
frutty [35]

Answer:

(9,-6)

(9,2)

(8,2)

(8,-6)

Step-by-step explanation:

To reflect something over the y axis all you have to do is change the sign of the X coordinate

which means that

(-9,-6) is (9,-6)

The other answers are

(9,2)

(8,2)

(8,-6)

4 0
2 years ago
PLZZ HELP I NEED ANSWER RNNNNNNB
poizon [28]

Answer:

Surface Area = 82.8 square meters

Volume = 37.96 cubic meters

Surface area:

6 × 2 = 12

9 × 2 = 18

8.8 × 6 = 52.8

12 + 18 + 52.8 = 82.8

Volume:

6 × 2 × 9.49 = 113.88

113.88 ÷ 37.96

5 0
3 years ago
Solve the graphs? Show Your Work?
kari74 [83]

4.\\x\leq10\\\\5.\\x\leq-4\\\\6.\\x\geq4

4 0
2 years ago
HURRRYYYY PLEASE ANSWER SUPER QUICK The table shows the relationship between x and y.
Alex17521 [72]

Answer:

  • 2 times

Step-by-step explanation:

According to the table, each value of y (dependent variable) is twice the corresponding value of x (independent variable).

This can be shown as

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5 0
2 years ago
Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
3 years ago
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