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miv72 [106K]
1 year ago
8

If the vault of y varies directly with x and y =-8 when x=4 find y when x =-4

Mathematics
1 answer:
Aloiza [94]1 year ago
8 0

Solution;

\begin{gathered} y\propto x \\ y=kx \end{gathered}\begin{gathered} When\text{ y=-8 and x=4;} \\ -8=4k \\ k=-\frac{8}{4}=-2 \end{gathered}\begin{gathered} When\text{ x=-4, y=?} \\ y=-2(-4) \\ y=8 \end{gathered}

Answer;

y=8

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An artist builds a sculpture out of metal and wood that weighs 14.9 kilograms. 3/4 of this weight is metal and the rest is wood.
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Answer:

Given is a sculpture that is built up of metal and wood, and the weight of this sculpture is 14.9 kilograms.

It says that three-fourth of the total weight is metal and says to find the weight of wooden part.

We can find the weight of metal part and then subtract it from the total weight to calculate the answer.

Total weight = 14.9 kilograms.

Metal part = three-fourth of total weight =

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Hence, the wooden part is 3.725 kilograms.

Step-by-step explanation:

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If x - 3 =4 <br> -2 (x + 5)<br> Then x =what?
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Step-by-step explanation:

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3 years ago
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4 years ago
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Answer:

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6 0
3 years ago
The edge of one cube is 4 m shorter than the edge of a second cube. The volumes of the two cubes differ by 1216 m^3. Find the ed
UkoKoshka [18]
Volume of cube, V = edge^3
Let edge of cube#1 = (x-4) m, therefore volume of cube#1, v1 = (x-4)^3 m
Let edge of cube#2 = x m, therefore volume of cube#2, v2 = x^3 m
Diff. in volume (in m) = 1216 = v2-v1 = [ x^3 - (x-4)^3 ] 
= x^3 - [(x-4)(x-4)(x-4)]
= x^3  - [<span>x^2 - 8x +16(x - 4)]
= </span> x^3 - [ x^3 - 12x^2 + 48x - 64 ]
= 12x^2 - 48x + 64
= 4 (3x^2 - 12x + 16)
Therefore 4 (3^2 - 12x + 16) = 1216
3x^2 - 12x + 16 = 1216/4 = 304
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(x-12) = 0
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7 0
3 years ago
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