Answer:
Given is a sculpture that is built up of metal and wood, and the weight of this sculpture is 14.9 kilograms.
It says that three-fourth of the total weight is metal and says to find the weight of wooden part.
We can find the weight of metal part and then subtract it from the total weight to calculate the answer.
Total weight = 14.9 kilograms.
Metal part = three-fourth of total weight =
Wooden part = 14.9 - 11.175 = 3.725 kilograms.
Hence, the wooden part is 3.725 kilograms.
Step-by-step explanation:
Answer:
someone help me with this ASAp
Step-by-step explanation:
Answer:
<h2><u>
r = -0.4</u></h2>
Step-by-step explanation: 57.7r + 23.23 = 2.57 57.7/57.7 = -20.66/57.7
- 23.23 - 23.23
57.7r = -20.66
Volume of cube, V = edge^3
Let edge of cube#1 = (x-4) m, therefore volume of cube#1, v1 = (x-4)^3 m
Let edge of cube#2 = x m, therefore volume of cube#2, v2 = x^3 m
Diff. in volume (in m) = 1216 = v2-v1 = [ x^3 - (x-4)^3 ]
= x^3 - [(x-4)(x-4)(x-4)]
= x^3 - [<span>x^2 - 8x +16(x - 4)]
= </span> x^3 - [ x^3 - 12x^2 + 48x - 64 ]
= 12x^2 - 48x + 64
= 4 (3x^2 - 12x + 16)
Therefore 4 (3^2 - 12x + 16) = 1216
3x^2 - 12x + 16 = 1216/4 = 304
3x^2 - 12x - 288 = 0
3 (x^2 - 4x - 96) = 0
(x^2 - 4x - 96) = 0
(x - 12) (x + 8) =0
(x-12) = 0
Therefore x = 12 m
Edge of cube#2 = x m = 12m
Edge of cube#1 = (x-4) m = 8m