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1 year ago

HELPDetermine the equation of the line shown in the graph:y = −1y = 0x = −1x = 0

Mathematics

1 answer:

astra-53 [7]1 year ago

8 0

in this problem we have a vertical line

The equation of a vertical line is equal to the x-coordinate of the point that passes through it

in this case

the equation of the line is

x=-1

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Help me do this i will pick brailest if right and it is 45 points!

sweet-ann [11.9K]

Answer:

8/21

Step-by-step explanation:

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3 years ago

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(6+9)2+6(600-9)+600 divide 30

Evgesh-ka [11]

Step-by-step explanation:

GIVEN

HERE

= 6+9+2+6+600÷30 { firstly add numbers }

= 623 ÷ 30

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2 years ago

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Carson and Jayden kept track of how many miles they ran during one week. Carson ran a total of 43 miles, which was 12 miles more

kozerog [31]

Answer:

Step-by-step explanation:

So the answer is 31 because

Carson ran 43

Jayden ran 12 miles less

so subtract 43-12=31

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3 years ago

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1) 130 words in 5 mins. How many words in an hour?

FinnZ [79.3K]

Answer:

Part 1) 1,560 words

Part 2) 161 miles

Step-by-step explanation:

Part 1) 130 words in 5 mins. How many words in an hour?

Remember that

$1\ hour=60\ min$

using proportion

Find out how many words in 60 minutes (one hour)

$\frac{130}{5}\ \frac{words}{min}= \frac{x}{60}\ \frac{words}{min}\\\\x=130(60)/5\\\\x=1,560\ words$

Part 2) 322 miles in 2 hours. How many miles in 60 minutes?

Remember that

$1\ hour=60\ min$

$2\ hours=120\ minutes$

using proportion

Find out how many miles in 60 minutes

$\frac{322}{120}\ \frac{miles}{min}= \frac{x}{60}\ \frac{miles}{min}\\\\x=322(60)/120\\\\x=161\ miles$

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3 years ago

In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y

daser333 [38]

The values of X and Y are 30 and 11 respectively

<h3>How to determine the values of X and Y?</h3>

The figure that represents the complete question is added as an attachment

The given parameters are:

DH = X +3

HF = 3Y

GH = 2X -5

HE = 5Y

From the attached parallelogram, we have:

DH = HF

GH = HE

Substitute the known values in the above equation

X + 3 = 3Y

2X - 5 = 5Y

Make X the subject in X + 3 = 3Y

X = 3Y - 3

Substitute X = 3Y - 3 in 2X - 5 = 5Y

2(3Y - 3) - 5 = 5Y

Expand

6Y - 6 - 5 = 5Y

Evaluate the like terms

Y = 11

Substitute Y = 11 in X = 3Y - 3

X = 3*11 - 3

Evaluate

X = 30

Hence, the values of X and Y are 30 and 11 respectively