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OLEGan [10]
2 years ago
8

Find the Area of the figure below, composed of a rectangle and a semicircle.

Mathematics
1 answer:
Mamont248 [21]2 years ago
3 0

Answer:

68.1 units²

Step-by-step explanation:

Start by finding the area of the rectangle...

Area=lw\\Area=6*9\\Area=54

Then, find the area of the semicircle...

Radius=\frac{1}{2}*Diameter=\frac{1}{2}*6=3

Area=\frac{1}{2}\pi r^2\\Area=\frac{1}{2}\pi 3^2\\Area=\frac{1}{2}\pi 9\\Area=\frac{9}{2}\ pi\\Area\approx14.1

Now, add the two to get...

54+14.1=68.1

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The cozy cat shop has 3 calico cats for every gray cat. If they have 9 calico cats available, how many gray cats do they have?
Leno4ka [110]
3 gray cats enjoy! (the rest of the typing here you may ignore its just to get 20 charactors) btw take 9/3 to get 3 gray cats because for every 3 calico there is one gray
6 0
3 years ago
Mr. Alfred’s car gets 12 miles per gallon. He drives to West Harlem for a weekend to visit his grandmother. He uses 6 gallons of
Kay [80]

Answer:

72 miles.

Step-by-step explanation:

If he uses 6 gallons of gas, you would do 6 (gallons he used) x 12 (miles per gallon) equaling 72.

6 0
3 years ago
Suppose you are given a cube made of magnesium (mg) metal of edge length 2.15 cm. (a) calculate the number of mg atoms in the cu
SVETLANKA909090 [29]

solution:

a) To calculate the volume of cube of edge 1.0cm

Volume= (edge)³

=(100cm) ³

= 1cm³

To find the mass of MG atoms  

Density = mass/volume

Mass of mg = 1.74g/cm³ x 1cm³

       = 1.74g

To find the number of mg atoms,

Molar mass of mg = 24.31g

24.31g mg contain 6.022 x 10²³ atoms of mg  

1.74g mg contain = 6.022 x 10²³mg atoms/24.31g mg x 1.74g mg

    = 0.4310 x 10²³mg atoms

    = 4.31 x 10²² mg atoms

B) to find the volume occupied by mg atoms  

    Total volume of cube = 1 cm³

    Volume occupied by mg atoms  

  = 74% of 1cm³

=74/100 x 1cm³= 0.74cm³

To find the volume of 1 mg atom  

4.31 x 10²² mg atoms occupy 0.74 cm³

1 atom will occupy 0.74cm³

1 atom will occupy = 0.74cm³/4.31 x 10²²mg atoms x 1mg atom

volume of 1 mg atom = 0.1716 x 10⁻²²cm²

Volume of 1 mg atom = 4/3 π³ in the form of sphere.

4/3πr³ = 0.1716 x 10⁻²²cm³

R³ = 0.1716 x 10⁻²²cm³x 4/3 x 7/22

R³ = 0.04095 x 10⁻²²cm³

R = 0.1599 x 10⁻⁷cm

1 = 10⁻¹⁰cm

 = 0.1599 x 10⁻⁷cm

 = 1pm/1 x 10⁻¹⁰cm  x 0.1599 x 10-7cm

= 1.599 x 10² pm  

R= 1.6 x 10²pm


3 0
2 years ago
−4(3m−3)+(−10+8m)=?
Valentin [98]
-4(3m-3)+(-10+8m)
12m+12-1+8m
12m+8m = 20m
+12 -1= +11
answer: 20m+11


*note negative times a negative equals positive and negative times positive is negative 
first: you multiply -4 by 3m which is -12m.
second: you multiply -4 by -3 which is +12
third: find the invisible which is 1. (located right here: +(1) (-10+8m)
fourth: multiply invisible 1 by -10 which is -10
fifth: multiply invisible one by +8m which is +8m 
sixth: combine like terms
seventh: answer
 
5 0
3 years ago
If angle 0 is in quadrant I, what is the value of
Brilliant_brown [7]

Answer:

the \: answer \: is \: c \:  =  -  \frac{ \sqrt{14} }{5}

Step-by-step explanation:

\sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2}  = 1( \sin^{2}0 +  \cos^{2} 0 = 1)

{ \sin }^{2}0 +  \frac{11}{25} = 1   \\  { \sin }^{2}0 =  \frac{14}{25}

\sin0_{1} =  -  \frac{ \sqrt{14}}{5} while \sin0_{2} =  \frac{ \sqrt{14} }{5}

  • Therfore theta is QI
  • Therfore sin theta >0
  • therefore \:  \sin0 =  \frac{ \sqrt{14} }{5}
4 0
1 year ago
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