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Tpy6a [65]
1 year ago
14

Grade Co... ▶ Da'yana Stover - Aerospace Engineering.pdf

Computers and Technology
2 answers:
SVEN [57.7K]1 year ago
8 0
The answer is Space shuttle.
DIA [1.3K]1 year ago
7 0

Answer:

The correct answer is c. Space shuttle, shuttle.

Explanation:

An aeronautical engineer would not work on a space shuttle because space shuttles are designed and built by aerospace engineers, not aeronautical engineers.

Aeronautical engineers focus on designing and building aircraft that operate within Earth's atmosphere, such as airplanes, helicopters, and zeppelins. Aerospace engineers, on the other hand, focus on designing and building spacecraft that operate outside of Earth's atmosphere, such as satellites, space stations, and space shuttles.

Therefore, the answer is c. Space shuttle, shuttle because it is not a type of machine that an aeronautical engineer would work on. The other choices (a. Zeppelin, b. Jet, and d. Airplane) are all types of machines that an aeronautical engineer might work on.

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Use JavaWrite a program that will simulate a change machine found at cash registers. Input the amount due and amount paid from t
Ksju [112]

Answer:

Here is the JAVA program:

import java.util.Scanner;  //to accept input from user

public class Main { // class name

 public static void main(String [] args) {  // start of main method

   Scanner input = new Scanner(System.in);  // creates Scanner class object to take input from user

   System.out.println("Please Enter the Cost of the Item: ");  // prompts user to enter the cost of item

   double itemCost = input.nextDouble();  //scans and reads the input value of item cost

   System.out.println("Please Enter the Amount Paid: ");  // prompts user to enter the amount paid

   double amount = input.nextDouble();  //scans and reads the value of amount from user

   int change = (int)(amount * 100 - itemCost * 100);  //compute the remaining amount i.e. change

   System.out.println("Change Owed: " + change / 100.0);  // displays the owed change

   int quarters = change / 25;  // computes the value for quarters

   change = change % 25;  // compute the quarters remaining

   int dimes = change / 10;  //  computes dimes

   change = change % 10;  //  computes dimes remaining

   int nickels = change / 5;  // computes nickels

   change = change % 5;  // compute nickels remaining

   int pennies = change;  // computes pennies

   System.out.println("Quarters: " + quarters);  // displays computed value of quarters

   System.out.println("Dimes: " + dimes);  // displays value of dimes

   System.out.println("Nickels: " + nickels);  // displays value of nickels

   System.out.println("Pennies: " + pennies);   }} //displays value of pennies

Explanation:

I will explain the program with an examples.

Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:

Change is computed as

change = (int)(amount * 100 - itemCost * 100);

This becomes;

change = (int)(5.00 * 100 - 4.57 * 100)

            = 500 - 457

change = 43

Now the change owed is computed as:

change / 100.0 = 43/100.0 = 0.43

Hence change owed = 0.43

Next quarters are computed as:

quarters = change / 25;

This becomes:

quarters = 43/25

quarters = 1

Now the remaining is computed as:

   change = change % 25;

This becomes:

   change = 43 % 25;

  change = 18

Next the dimes are computed from remaining value of change as:

dimes = change / 10;

dimes = 18 / 10

dimes = 1

Now the remaining is computed as:

   change = change % 10;

This becomes:

   change = 18 % 10

  change = 8

Next the nickels are computed from remaining value of change as:

nickels = change / 5;

nickels = 8 / 5

nickels = 1

Now the remaining is computed as:

   change = change % 5;

This becomes:

   change = 8 % 5

  change = 3

At last the pennies are computed as:

pennies = change;

pennies = 3

So the output of the entire program is:

Change Owed: 0.43                                                                                                                Quarters: 1                                                                                                                      Dimes: 1                                                                                                                         Nickels: 1                                                                                                                       Pennies: 3  

The screenshot of the output is attached.

7 0
3 years ago
​Microsoft claims that the microsoft project software can _____.
Lina20 [59]
The Microsoft project software is designed in assisting the project manager in formulating plans, distributing resources to certain tasks, progress monitoring, budget management and analysis of workloads.

I hope I was able to help you. Thank you for posting your question here at Brainly.
8 0
3 years ago
Suppose you're trying to remove the clamp from a ground strap that's connected to a battery. The clamp won't come loose. Which o
Mekhanik [1.2K]
The answer would be B.
5 0
3 years ago
Read 2 more answers
C++
Nookie1986 [14]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

class Window //defining a class Window

{

private:

int width, height;//defining integer variable

public:

friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters

{

return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values

}  

Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters  

{}

};

int main() //Main method

{

Window w(80,90);//calling class constructor

cout<<w;//print object value

return 0;

}

Output:

a (80 x 90) window

Explanation:

In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.

Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.

7 0
3 years ago
Determine the value of X if (211) base x = (152) base 8, how to do this?
Alex
 we translate the following statement given in terms of logarithms. 211 base x can be expressed into log 211 / log x while 152 base 8 can be expressed int o log 152 over log 8. In this case,
log 211 / log x = log 152 / log 8log x = 0.962x = 10^0.962 = 9.1632
7 0
3 years ago
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