Answer:
Explanation:
The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.
public static T minmax(ArrayList<T> mylist) {
T min = new T();
T max = new T();
for (int x = 0; x < mylist.size(); x++) {
if (mylist.get(x) > max) {
max = mylist.get(x);
} else if (mylist.get(x) < min) {
min = mylist.get(x);
}
}
return (min, max);
}
Answer:
A) True
Explanation:
Industrial espionage utilizes both illegal and unethical methods in gathering information about a corporate organization in order to get business intelligence. This involves stealing intellectual property and trade secrets to use them for a competitive advantage. because Information about company's products, services, finances, sales, etc can be toold for economic warfare
Answer: b)because near-critical paths could become critical paths with small delays in these activities
Explanation: Program evaluation and review technique(PERT) technique is used for management of the project .The organizing, maintenance,coordination of any task is done by this chart. The non-critical activities need to be observed carefully because they may create near-critical methods which can lead to complexity.
Other options are incorrect because not all activities are equally rather monitoring is done to avoid errors and slack can occur at any path . Small delays can be caused but not complete project can get delayed and there can be risk of complexity rather than being uncompleted.Thus, the correct option is option(b).
Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
