Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
11.2 x 11 x 8 is 985.6
so uh- yeah i hope that helped lol
I don’t know if this is correct but about 4 times because
3/4 -> 18/24 and 1/6 -> 4/24
Answer:
9.5
Step-by-step explanation:
Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance.
Step 1
We find the Mean of the numbers
Mean = Sum of terms/ Number of terms
Mean = 9+12+9+14+6/5
= 50/5
= 10
Step 2
We find the sample variance
Formula =
(x - Mean)²/n - 1
n = 5
= (9 - 10)²+(12 -10)²+(9- 10)²+(14-10)²+(6-10)²/5 - 1
= 1+ 4+ 1+ 16+16/5 - 1
= 38/5 - 1
= 38/4
= 9.5
Therefore, Sample variance = 9.5