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podryga [215]
3 years ago
5

What would the answers to these be?

Mathematics
1 answer:
amm18123 years ago
4 0

The first equation, 8x - 9y = - 23

Obtain the equation in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = ( \frac{1}{2}, 3) and (x₂, y₂ ) = (- 4, - 1 )

m = \frac{-1-3}{-4-1/2} = (- 4)/- \frac{9}{2} = \frac{8}{9}

partial equation is y = \frac{8}{9} x + c

to find c substitute either of the 2 points into the partial equation

using (- 4, - 1 ), then

- 1 = - \frac{32}{9} + c ⇒ c = \frac{23}{9}

y = \frac{8}{9} x +\frac{23}{9} ← in slope- intercept form

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

rearrange the slope- intercept equation into this form

multiply through by 9

9y =  8x + 23 ( subtract 9y and 23 from both sides )

8x - 9y = - 23 in standard form


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A number pattern starts with 4 and follows the rule add 5 what er the first five numbers in the pattern
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Step-by-step explanation:

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3 years ago
What transformation has changed the parent function f(x) = (.5)x to its new appearance shown in the graph below?
Simora [160]

Answer:

Last option

−1 • f(x)

Step-by-step explanation:

The function f(x) = (0.5) ^ x passes through point (-1, 2) because:

f(-1) = (0.5) ^ {-1}= \frac{1}{(0.5)} = 2

and also goes through the point (0, 1)

Because:

f(0) = (0.5)^0 = 1

Then, if the transformed function passes through the point (0, -1) and passes through the point (-1, -2) then this means that the graph of f(x) = (0.5) ^ x reflected on the axis x. This means that if the point (x_0, y_0) belongs to f(x), then the point (x_0, -y_0) belongs to the transformed function

The transformation that reflects the graph of a function on the x-axis is.

y = cf(x)

Where c is a negative number. In this case c = -1

Then the transformation is:

y = -1*f(x)

and the transformed function is:

f (x) = - (0.5) ^ x

<h2><em><u>Observe the attached image.</u></em></h2>

8 0
3 years ago
Read 2 more answers
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