1 year ago

G is located at (0, 4)What are the coordinates of G' after G undergoes the translation (x,y)-> (x-5,y+2)?

Mathematics

1 answer:

oksian1 [2.3K]1 year ago

7 0

Applying the translation rule:

G(0, 4) → (0-5, 4+2) → G'(-5, 6)

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%20%20%5Cdiv%202%20%2B%202%20%5Cdiv%20%20%5Csqrt%7B2%20%7D%20" id="TexForm

NeX [460]

Answer:

$\frac{3\sqrt{2} }{2}$

Step-by-step explanation:

Given

$\frac{\sqrt{2} }{2}$ + $\frac{2}{\sqrt{2} }$ ← rationalise the denominator by multiplying by $\frac{\sqrt{2} }{\sqrt{2} }$

= $\frac{\sqrt{2} }{2}$ + ( $\frac{2}{\sqrt{2} }$ × $\frac{\sqrt{2} }{\sqrt{2} }$ )

= $\frac{\sqrt{2} }{2}$ + $\frac{2\sqrt{2} }{2}$

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$

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