5x-8y=1...(1)
3x+6y=-21...(2)
(1)*3:
15x-24y=3...(3)
(2)*5:
15x+30y=-105...(2)
(3)-(2):
15x-24y-(15x+30y)=3-(-105)
15x-24y-15x-30y=108
-54y=108
y=-2
Answer: x = 2
<u>Step-by-step explanation:</u>

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Answer: x = 0
<u>Step-by-step explanation:</u>

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Answer: No Solution
<u>Step-by-step explanation:</u>

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Answer: No Solution
<u>Step-by-step explanation:</u>
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By setting up a system of equations we can easily solve this problem. Let's denote Jane's working hours with x and Jack's working hours with y. Since they don't want to work more than 65 hours, the first equation is x+y=65. The second equation is 14x+7y=770. By solving this system of equation

, we find that y=20 hours, which is Jack's maximum working hours.
51/5 is equivalent to 10 and 1/5.
Answer:

Explanation:
From the question, we have it that the probability of heads coming up every time or tail coming up every time is 1:7 if the coin is tossed in 4 tosses
What this means is that we have a probability of 1/8 of head showing up and a probability of 7/8 that a tail will show up in each toss of the coin
For four throws, it means all four are heads or all four are tails
If all four are heads, we have the probability of this happening as:

if all four are tails, we have the probability as:

Now, the probability of either heads or all tails after 4 tosses will be: