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mafiozo [28]
1 year ago
11

These five frames show a shapes different positions

Mathematics
1 answer:
kipiarov [429]1 year ago
7 0

From the attached image, we can tell that:

From 1 to 2: There is a shift from left to right along the same plane (x-axis).

From 2 to 3: There is a 90° rotation in the clockwise direction.

From 3 to 4: There is a negative vertical shift. Assuming a y-axis this would be from the top down.

From 4 to 5: There is a 180° rotation in the clockwise direction.

<h3>What is a rotation?</h3>

It is to be noted that a rotation is a sort of transformation that rotates each point in a figure a specific number of degrees around a particular point.

Learn more about rotation in math:
brainly.com/question/26249005
#SPJ1

Full Question:

These five frames (in the attached image_ show shapes of different positions. Describe how the shape moves to get from its position in each frame to the next.

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Where dose - 11/10 go on a number line
viva [34]

Well, -11/10 is also -1.1. So, it goes right next to -1 on a number line.

6 0
3 years ago
Subtact: (7x + 5) - (3x + 2)​
-Dominant- [34]

Answer:

4x+3

Step-by-step explanation:

subtract 7-3 =4 then you subtract 5-2=3. put it together 4x+3

5 0
3 years ago
Read 2 more answers
What is the results of adding these two equations?<br> 6x+2y=-2<br> 3x-2y=-5
Bess [88]

Answer:

x=-7/9, y=4/3. (-7/9, 4/3).

Step-by-step explanation:

6x+2y=-2

3x-2y=-5

-----------------

9x=-7

x=-7/9

6(-7/9)+2y=-2

-42/9+2y=-2

2y=-2-(-42/9)

2y=-2+42/9

2y=-18/9+42/9

2y=24/9

y=(24/9)/2

y=(24/9)(1/2)

y=24/18

y=4/3

5 0
3 years ago
Twenty more than four times a number is equal to the difference between −71 and three times the number. Find the number.
anzhelika [568]

4x + 20 = - 71 - ( 3x )

4x + 20 = - 3x - 71

Subtract sides minus 20

4x + 20 - 20 = - 3x - 71 - 20

4x = - 3x - 91

Add sides 3x

4x + 3x = - 3x + 3x - 91

7x = - 91

Divide sides by 7

7x / 7 = - 91 / 7

Simplification

x = - 13

Thus the number is ( - 13 ) .

3 0
3 years ago
The following measurements (in picocuries per liter) were recorded by a set of argon gas detectors installed in a research facil
Reptile [31]

Answer:

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

Step-by-step explanation:

Before building the confidence interval, we have to find the sample mean and the sample standard deviation.

Sample mean:

\overline{x} = \frac{381.3+394.8+396.1+380}{4} = 388.05

Sample standard deviation:

s = \sqrt{\frac{(381.3-388.05)^2+(394.8-388.05)^2+(396.1-388.05)^2+(380-388.05)^2}{3}} = 8.58

Confidence interval:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 3.1824

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 3.1824\frac{8.58}{\sqrt{4}} = 13.65

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 388.05 - 13.65 = 374.4

The upper end of the interval is the sample mean added to M. So it is 388.05 + 13.65 = 401.7

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

4 0
3 years ago
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