Answer:
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9514 1404 393
Answer:
(c) CPCTC
Step-by-step explanation:
The proof might go something like this:
- EH ≅ KH, FH ≅ JH . . . . . given
- ∠EHF ≅ ∠KHJ . . . . . vertical angles are congruent
- ∆EHF ≅ ∆KHJ . . . . . SAS congruence theorem
- EF ≅ KJ . . . . . CPCTC
Note that JK is an alternate name for segment KJ. We used KJ in the proof because vertices K and J correspond directly to vertices E and F in the congruent triangles.
Answer:
1.99
Step-by-step explanation:
Answer:
(- 3, 5 )
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x + 3)² + (y - 5)² = 1 ← in standard form
with centre = (h, k) = (- 3, 5 )
Answer:
2 1/3 years
Step-by-step explanation:
4 months = 1/3 years
2 + 1/3 = 2 1/3 years