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Alex73 [517]
1 year ago
10

Write an SQL statement to display for every restaurant the name of the restaurant (where the name of the restaurant consists of

more than 10 characters) and for every category of menu item its description (catdesc). Furthermore, display the average; cheapest or lowest; and highest or most expensive price of all menu items in that category at that restaurant. Use single row functions to format all the prices. The average price must be padded; the cheapest price must be rounded; but the highest price must not be rounded. Display only those menu items of which the average item price is more than R40. Sort your results according to the restaurant names and for every restaurant from the most expensive average menu item to the cheapest average menu item. Display your results exactly as listed below.
Computers and Technology
1 answer:
Rainbow [258]1 year ago
4 0

Using the knowledge in computational language in SQL it is possible to write the code that display for every restaurant the name of the restaurant  and for every category of menu item its description.

<h3>Writting the code:</h3>

<em>INSERT INTO Dish </em><em>Values</em><em>(13, 'Spring Rolls', 'ap');</em>

<em>INSERT INTO Dish Values(15, 'Pad Thai', 'en'); </em>

<em>INSERT INTO Dish Values(16, 'Pot Stickers', 'ap');    </em>

<em>INSERT INTO Dish Values(22, 'Masaman Curry', 'en');   </em>

<em>INSERT INTO Dish Values(10, 'Custard', 'ds');   </em>

<em>INSERT INTO Dish Values(12, 'Garlic Bread', 'ap');    </em>

<em>INSERT INTO Dish Values(44, 'Salad', 'ap');    </em>

<em>INSERT INTO Dish Values(07, 'Cheese Pizza', 'en');   </em>

<em>INSERT INTO Dish Values(19, 'Pepperoni Pizza', 'en');    </em>

<em>INSERT INTO Dish Values(77, 'Veggie Supreme Pizza', 'en');</em>

<em />

<em>INSERT </em><em>INTO MenuItem Values(0, 0, 13, 8.00);</em>

<em>INSERT INTO </em><em>MenuItem </em><em>Values(1, 0, 16, 9.00);</em>

<em>INSERT INTO MenuItem Values(2, 0, 44, 10.00);</em>

<em>INSERT INTO MenuItem Values(3, 0, 15, 19.00);</em>

<em>INSERT INTO MenuItem Values(4, 0, 22, 19.00);</em>

<em>INSERT INTO MenuItem Values(5, 3, 44, 6.25);</em>

<em>INSERT INTO MenuItem Values(6, 3, 12, 5.50);</em>

<em>INSERT INTO MenuItem Values(7, 3, 07, 12.50);</em>

<em>INSERT INTO MenuItem Values(8, 3, 19, 13.50);</em>

<em>INSERT INTO MenuItem Values(9, 5, 13, 6.00);</em>

<em>INSERT INTO MenuItem Values(10, 5, 15, 15.00);</em>

<em>INSERT INTO MenuItem Values(11, 5, 22, 14.00);</em>

See more about SQL atbrainly.com/question/13068613

#SPJ1

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Answer:

The modified program in Python is as follows:

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

wall_width = int(input('Enter wall width (feet):\n'))

area = wall_height*wall_width

print('Wall area:',area,'square feet')

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print('Paint needed: {:.2f} gallons'.format(paint_needed))

print('Cans needed:',round(paint_needed),'can(s)')

color = input("Choose a color to paint the wall: ")

print("Cost of purchasing", color, "paint: $",paint_colors[color])

Explanation:

The italicized are given from the question [unchanged]

<em>import math</em>

<em> paint_colors = {'red': 35,'blue': 25,'green': 23} </em>

<em>wall_height = int(input('Enter wall height (feet):\n')) </em>

This gets input for width

wall_width = int(input('Enter wall width (feet):\n'))

Calculate the wall area

area = wall_height*wall_width

Print the calculated wall area

print('Wall area:',area,'square feet')

Calculate the amount of paint needed

paint_needed = area/350.0

Print the amount of paint needed to 2 decimal places

print('Paint needed: {:.2f} gallons'.format(paint_needed))

Print the amount of can needed to nearest integer

print('Cans needed:',round(paint_needed),'can(s)')

Prompt user for color of paint [here, we assume the user input is correct]

color = input("Choose a color to paint the wall: ")

Prints the corresponding amount for the color

print("Cost of purchasing", color, "paint: $",paint_colors[color])

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Find the number of ways in which a committee of 4 can be chosen from six boys and
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Answer:

465 ways

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2 girls ; 2 boys = 6C2 ; 6C2

3 girls ; 1 boy = 6C3 ; 6C1

(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)

Combination formula:

nCr = n! ÷ (n-r)!r!

We can also use a calculator :

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Hence,

(6C1 * 6C3) + (6C2 * 6C2) + (6C3 * 6C1)

(6 * 20) + (15 * 15) + (20 * 6)

120 + 225 + 120

= 465 ways

6 0
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