What is the y- intercept of the quadratic function below ?
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3x - 2x + 4 = 5x - 4x - 8
First, let's focus on the left side of the problem (3x - 2x + 4). Let's subtract 3x - 2x which will get us 1, and since a variable by itself is considered 1, we can just put the variable.
Second, now let's focus on the right side of the problem (5x - 4x - 8). Subtract 5x - 4x to once again get 1. Replace it with the variable and leave the rest.
Third, we can now cancel out x on each side. This will leave us with 4 = -8, which is false, meaning that there is no solution to this problem.
First, let's focus on the left side of the problem (3x - 2x + 4). Let's subtract 3x - 2x which will get us 1, and since a variable by itself is considered 1, we can just put the variable.
Second, now let's focus on the right side of the problem (5x - 4x - 8). Subtract 5x - 4x to once again get 1. Replace it with the variable and leave the rest.
Third, we can now cancel out x on each side. This will leave us with 4 = -8, which is false, meaning that there is no solution to this problem.
Let point A be and point B
Use the point-slope formula and whichever point you want as , in this case I'll use