<span>p1=44/88=.50; p2=57/85=.67.
Under the null hypothesis of no difference, we pool the data to estimate the
common p of (44+57)/(88+85)=.584.
The test statistic is (.67-.50)/sqrt[(.584)(1-.584)(1/88 + 1/85)]=2.268 (which is stat sig. at a .095 level).</span>
Answer:

Step-by-step explanation:
Given

Now we know that system has infinite solution for x

in above equation.

∴
Answer:
A. $41.99
B. $18.00
Step-by-step explanation:
To find discount: 59.99×0.7= 41.99
To find sales price: 59.99-41.99=18
(3) 62.5% cuz u take the total number of the students and u divide it by the number of students between 60 to 65
Answer:
8428
Step-by-step explanation:
According to the Question,
- Given, A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row.
We have a number sequence 13, 18, 23, ...
- We can say that this is an arithmetic sequence because of the common difference 'd', is equal to 5, and the first term 'a1' is equal to 13.
- The formula for the sum of an arithmetic sequence with n terms is given is
.
Substitute the given values into the equation to solve for the sum of the 56 rows of seats.
![S_56= \frac{56}{2}[2(13)+(56-1)(5)]\\S_{56}=28\left[26+275\right]\\S_{56}=28\left[301\right]\\S_{56}=8428](https://tex.z-dn.net/?f=S_56%3D%20%5Cfrac%7B56%7D%7B2%7D%5B2%2813%29%2B%2856-1%29%285%29%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B26%2B275%5Cright%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B301%5Cright%5D%5C%5CS_%7B56%7D%3D8428)
Therefore, there are 8428 seats in all.