Answer:
x = 3/2 | y = -3
Step-by-step explanation:
Given equations:
- y = 2x - 6. . . .(i)
- y = -4x + 3. . . . (ii)
Substituting from equation (i) for y:
==> 2x - 6 = -4x + 3
==> 2x + 4x = 6 + 3
==> 6x = 9
<em>dividing both </em><em>sides by 3</em><em>:</em>
==> 2x = 3
==> x = 3/2
Substituting 3/2 for x in equation (i):
==> y = 2(3/2) - 6
==> y = 3 - 6
==> y = -3
The equation y - 2 = -5(x - 2) represents a linear function ⇒ 1st answer
Step-by-step explanation:
A linear function is any function that graphs to a straight line
(not a vertical line)
The forms of the linear equation are
- y = m x + b, where m is the slope of the line which represents the function and b is the y-intercept ⇒ slope-intercept form
, where m is the slope and
is a point lies on the line which represent the function ⇒ slope-point form- Ax + By = C, where A, B, and C are constant ⇒ standard form
Linear function means the greatest power x and y in the equation of the function is 1
∵ The equation is y - 2 = -5(x - 2)
∵ The greatest power of x and y is 1
∵ The equation is in the form of
, where
m = -5 and the coordinates of the point are (2 , 2)
∴ The equation represents a linear function
The equation y - 2 = -5(x - 2) represents a linear function
Learn more:
You can learn more about the linear function in brainly.com/question/4326955
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Answer:
B. 0.025
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that,
y' = 17y ( 1-y^7)
Let y=1
Then, y' = 0 for all t
Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.
So, the graph solution will be
y(0) = 1 and this will be an horizontal line
If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.
Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.
So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.
This make the limit be 1.
This shows that x = 1 is a stable equilibrium.