Question

The value of the algebraic expression below. 6a^3 + (4b-c)^2 ÷2 When... A=5 B=3C=2Please view the picture

Answer 1

You have the expression:

$\frac{6a^3+(4b-c)^2}{2}$

And the given values are:

a=5

b=3

c=2

You substitute the given values in the equation:

$\frac{6(5^3)+(4(3)-2)^2}{2}$

Then you make the opperations:

$\frac{6(125)+(12-2)^2}{2}$$\frac{750+10^2}{2}$$\frac{750+100}{2}$$\frac{850}{2}$Finally, you get:$\frac{850}{2}=425$