I might not respond for a little while, please don’t end the session! Need help on #3 and 4
1 answer:
We have a right triangle with a 15m hypotenuse and a 8m leg. If we use x for the missing leg then the Pythagorean Theorem states that:

Then we have to solve that equation for x:
![\begin{gathered} x^2=15^2-8^2=225-64 \\ x^2=161 \\ x=\sqrt[]{161} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2%3D15%5E2-8%5E2%3D225-64%20%5C%5C%20x%5E2%3D161%20%5C%5C%20x%3D%5Csqrt%5B%5D%7B161%7D%20%5Cend%7Bgathered%7D)
So the answer is the square root of 161.
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Answer:
(20.60-5)/0.10=156 Papers
Step-by-step explanation:
1: 144 because
4 * 15 = 60 ft total height = 720 in total height
5: 720 = 1: 144
The answer is 6500 decigrams. I hope that helps
Y’all up for the time of your time