1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
borishaifa [10]
1 year ago
14

Cengage Homework Trig/Pre-calc

Mathematics
1 answer:
iVinArrow [24]1 year ago
3 0

Based on the populations of the town from 2000 to 2008, the average rate of change of the population between 2002 and 2004 is -6.1%

The average rate of change between 2002 and 2006 is -4.88%

<h3>What is the average rate of change?</h3>

The average rate of change can be found as:

=Change in population / Population in base year

The average rate of change in population between 2002 and 2004 is:

= (77 - 82) / 82

= -6.1%

The average rate of change in population between 2002 and 2006 is:

= (78 - 82) / 82

= -4.88%

Find out more on the average rate of change at brainly.com/question/23434598

#SPJ1

You might be interested in
Help is good at math
rodikova [14]
I believe it would be 3/8
8 0
3 years ago
Read 2 more answers
Draw an array for the equation. 5+5+5+5+5=25
Artist 52 [7]
5 times 5 can be array for 5+5+5+5+5=25
8 0
3 years ago
Read 2 more answers
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 83 type K batteries and a sample of 77
agasfer [191]

Answer:

1. Null Hypothesis, H_0 : \mu_1 = \mu_2  {mean voltage for these two types of

                                                         batteries is same}

Alternate Hypothesis, H_1 : \mu_1\neq \mu_2 {mean voltage for these two types of

                                                            batteries is different]

2. Test Statistics value = -5.06

4. Decision for the hypothesis test is that we will reject null hypothesis.

Step-by-step explanation:

We are given that an engineer is comparing voltages for two types of batteries (K and Q).

where, \mu_1 = true mean voltage for type K batteries.

            \mu_2 = true mean voltage for type Q batteries.

So, <em>Null Hypothesis, </em>H_0<em> : </em>\mu_1 = \mu_2<em>  {mean voltage for these two types of </em>

<em>                                                          batteries is same}</em>

<em>Alternate Hypothesis, </em>H_1<em> : </em>\mu_1\neq \mu_2<em> {mean voltage for these two types of </em>

<em>                                                             batteries is different]</em>

The test statistics we use here will be :

                          \frac{(X_1bar-X_2bar) - (\mu_1 - \mu_2) }{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }   follows t_n__1+n_2-2

where, X_1bar = 9.29         and      X_2bar =  9.65

                s_1    = 0.374       and             s_2 =  0.518

                 n_1   = 83            and             n_2  =  77

                  s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} } =   \sqrt{\frac{(83-1)0.374^{2}+(77-1)0.518^{2}  }{83+77-2} } = 0.45                                                   Here, we use t test statistics because we know nothing about population standard deviations.

      Test statistics = \frac{(9.29-9.65) - 0 }{0.45\sqrt{\frac{1}{83}+\frac{1}{77}  } }  follows t_1_5_8

                              = -5.06

<em>At 0.05 or 5% level of significance t table gives a critical value between (-1.98,-1.96) to (1.98,1.96) at 158 degree of freedom. Since our test statistics is less than the critical table value of t as -5.06 < (-1.98,-1.96) so we have sufficient evidence to reject null hypothesis.</em>

Therefore, we conclude that mean voltage for these two types of batteries is different.

7 0
3 years ago
Avicenna, a major insurance company, offers five-year life insurance policies to 65-year-olds. If the holder of one of these pol
ki77a [65]

Answer:

Avicenna can expect to lose money from offering these policies. In the long run, they should expect to lose ___33__ dollars on each policy sold

Step-by-step explanation:

Given :

The amount the company Avicenna must pay to the shareholder if the person die before 70 years = $ 26,500

The value of each policy = $497

It is given that there is a 2% chance that people will die before 70 years and 98% chance that people will live till the age 70.

The expected policy to be sold= policy nominal + chances of death

                                      = 497 + [98% (no pay) + 2% (pay)]

                                     = 497 + [98%(0) + 2%(-26500)]

(The negative sign shows that money goes out of the company)

                                   = 497 - 2% (26500)

                                  = 497 - 530

                                  =33

Therefore the company loses 33 dollar on each policy sold in the long run.

7 0
3 years ago
Algebra question please help!
konstantin123 [22]

Answer: the answer is s = -19

5 0
3 years ago
Other questions:
  • The smartest person can only help with the method please help <br> 3 1/4 divided by 2
    10·1 answer
  • Match the equation with its corresponding solution for x. 4x + 7 = 35
    5·1 answer
  • a park is in the shape of a rectangle 8 miles long and 6 miles wide. how much shorter is your walk if you walk diagonally across
    14·1 answer
  • Ayy yall know what's 75 x 100
    11·1 answer
  • Find the mean of the data in the dot plot below vitamins
    12·2 answers
  • Keisha wants to buy a stereo. Her mother said if Keisha saved 75% of the cost of the stereo, she would pay the other 25% and the
    12·1 answer
  • Can someone help me with the questions in the picture?
    8·1 answer
  • What is the value of n? Write your answer as a number only
    7·1 answer
  • Find all the real zeros of the function y = -6x - 5<br> A -5/6 B 5/6 C -6 D -6, -5
    8·1 answer
  • I do not know the answer for this
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!