3 years ago

Is LMN ~ QPQ? If so, name the congruence postulate that applies

Mathematics

1 answer:

OverLord2011 [107]3 years ago

4 0

Where is the pic bro......✌✌✌.........??????how can I tell u without the picture..???

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Triangle and triangle are similar. What is the measure of side ?

snow_lady [41]

When two triangles are similar, they're sides are in proportion.

In order to find the unknown side, we first have to find the ratio of the larger triangle to the smaller triangle.

We can use the sides TV and LN to make the proportion.

$\frac{LN}{TV}$ = $\frac{21}{6}$

The ratio between the two triangles is 21:6

Now we can solve for the unknown side.

$\frac{21}{6}$ = $\frac{LM}{8}$

Cross multiply:

8 * 21 = 6 * LM

168 = 6LM

Divide both sides by 6:

LM = 28

The unknown side's length is 28 centimeters

Good luck!

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2 years ago

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190 m<br> 90 m<br> 10 m<br> 40 m<br> What is the area

liberstina [14]

Answer:

Rect Area= Lw

3D Rect Area= 2(wh+lw+lh)

Step-by-step explanation:

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3 years ago

The sum of the digits of a two-digit number is 10. When the digits are reversed, the new number is 18 less than the original num

eimsori [14]

<h3>Answer:</h3>

<h3>Explanation:</h3>

6+4= 10

Then reverse the digits of 64, and you have 46

64-46= 18

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3 years ago

Phoenix is selling cookies for $2 each and cups of lemonade for $1.50 each. She hopes to raise $50. On scratch paper, write an e

Nadusha1986 [10]

You can divide 50 by 5 (2+(1.50x2)) 50/5 is 10 10x + 20y.

Happy studying ^-^

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2 years ago

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago