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EastWind [94]
1 year ago
15

What is the area of the shaded part?

Mathematics
1 answer:
makvit [3.9K]1 year ago
4 0
C) 225m

Explanation:
Looking at the board we see each side is 25m in length. Each side has 5 squares, therefore the length of one side of each square is 5m (25m/5=5).

Let’s count how many full squares there are. There’s 5 completely full squares (one in the middle, and one on each of the four edges).

There’s also half-full squares which we COULD calculate separately using the area of a triangle. However, we know that two halves make one full square so let’s count how many full blocks these make up. There’s 8 triangles (or half full squares), therefore there are 4 full squares.

Adding this to the clearly full blocks shows 4+5=9. There are 9 fully shaded squares. The area of a square is A=s x s (Area = length of side x length of side). Therefore, one square’s area is 5x5=25m^2. The area of 9 squares is 25 x 9 = 225m^2.

Therefore the answer is C
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Answer:

x = 4.167

Step-by-step explanation:

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8x = 2x + 25 subtract 2x to 2x and 8x

6x = 25 divide by 6

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Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

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12 (2 -2)+32 = (x +6) +2
Anestetic [448]

Answer: x = 24

Step-by-step explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

<u>Step 1:</u><u> </u><u><em>Remove parentheses.</em></u>

12 (2 − 2) + 32 = x + 6 + 2

<u>Step 2:</u><u> </u><u><em>Simplify 2 − 2 to 0.</em></u>

12 × 0 + 32 = x  + 6 + 2

<u>Step 3:</u><u> </u><u><em>Simplify 12 × 0 to 0.</em></u>

0 + 32 = x +  6 + 2

<u>Step 4:</u><u> </u><u><em>Simplify 0 + 32 to 32.</em></u><em> </em>

32 = x + 6 + 2

<u>Step 5:</u><u> </u>x<u><em> + 6 + 2 to </em></u>x<u><em> + 8.</em></u>

32 = x + 8

<u>Step 6:</u><u> Subtract 8 from both sides.</u>

32 − 8 = x

<u>Step 7:</u><u> Simplify 32 − 8 to 24.</u>

24 = x

<u>Step 8:</u><u> </u><u><em>Switch sides.</em></u>

x = 24

~I hope I helped you! :)~

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