FREEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEETHINGSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSEE
1 answer:
You might be interested in
The reflection of BC over I is shown below.
<h3>What is reflection?</h3>- A reflection is a mapping from a Euclidean space to itself that is an isometry with a hyperplane as a set of fixed points; this set is known as the reflection's axis (in dimension 2) or plane (in dimension 3).
- A figure's mirror image in the axis or plane of reflection is its image by reflection.
See the attached figure for a better explanation:
1. By the unique line postulate, you can draw only one line segment: BC
- Since only one line can be drawn between two distinct points.
2. Using the definition of reflection, reflect BC over l.
- To find the line segment which reflects BC over l, we will use the definition of reflection.
3. By the definition of reflection, C is the image of itself and A is the image of B.
- Definition of reflection says the figure about a line is transformed to form the mirror image.
- Now, the CD is the perpendicular bisector of AB so A and B are equidistant from D forming a mirror image of each other.
4. Since reflections preserve length, AC = BC
- In Reflection the figure is transformed to form a mirror image.
- Hence the length will be preserved in case of reflection.
Therefore, the reflection of BC over I is shown.
Know more about reflection here:
#SPJ4
The question you are looking for is here:
C is a point on the perpendicular bisector, l, of AB. Prove: AC = BC Use the drop-down menus to complete the proof. By the unique line postulate, you can draw only one segment, Using the definition of, reflect BC over l. By the definition of reflection, C is the image of itself and is the image of B. Since reflections preserve , AC = BC.
The difference is .
Step-by-step explanation:
Step 1:
The polynomial is subtracted from the polynomial
.
If we write this as an equation, we get
.
To subtract the polynomials, we group up the terms based on their variables.
In this subtraction, there are two variables i.e. and
and there is one constant term.
Step 2:
The subtraction of the variables;
.
The subtraction of the variables;
.
The subtraction of the constants; .
So .