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1 year ago

What's 2 over 5th plus 2 over 10th

Mathematics

1 answer:

sergij07 [2.7K]1 year ago

6 0

The expression we need to solve is:

$\frac{2}{5}+\frac{2}{10}$

To solve this problem, we need to not that we can simplify the fraction 2/10 by dividing both number by 2:

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Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms con

pav-90 [236]

$Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}$

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3 years ago

John ran 4 laps of the track in 5 minutes, 40 seconds

mihalych1998 [28]

Well, lets think about this. We need to ask our self how many seconds are in one minute. There are 60 seconds in 1 minute. We know he did 4 laps in 5 minutes and 40 seconds. You can change the minutes to seconds by multiplying 60 * 5 = 300 seconds. So 5 minutes = 300 seconds. Now just take the 40 seconds and add it to the 300 seconds, which will give you 340 seconds. So John ran 4 laps in 340 seconds. B wants to know how many seconds it took John per lap...We can find this by dividing 340 by 4 340/4 = 85.

A) 340 seconds

B) 85 sec/lap

7 0

3 years ago

Read 2 more answers

The range of the following relation R {(3,-2), (1,2), (-1,-4),(-1,2)}

Phantasy [73]

The answer is to this question is b

4 0

2 years ago

Determine whether each function is continuous at x=5. Justify your answer using the continuity test.

irakobra [83]

Answer:

2. $f(x)=\frac{x^2}{x+5}$

Step-by-step explanation:

When you replace x=5 into those functions you obtain:

$1. f(x)=\sqrt{x^2-36} = \sqrt{5^2-36} = \sqrt{-11} \\2. f(x)=\frac{x^2}{x+5}=\frac{5^2}{5+5}=\frac{25}{10}$

We can see that the function number 1, when the x=5 is replaced, falls into the imaginary numbers or complex domain, so the function is not continuous in the real domain.

On the other hand, the second function falls into the real domain whe x=5 is replaced, so the function is continuous in the real domain!

I hope you understand!

6 0

3 years ago

Keller boat travels 24mph. find the rate of the river if she can travel 6 mi upstream. in the same amount of time she can go 10

nikitadnepr [17]

The correct answer is:

6 mph.

Explanation:

We will use the formula d = rt for this, where d is distance, r is rate, and t is time.

We know that the time for both distances is the same; this means we want to isolate t in our formula. To do this, we will cancel r by dividing both sides:
d/r = rt/r
d/r = t

We will write an expression for the time upstream, an expression for the time downstream, and set them equal.

For the time upstream, the distance is 6 and the rate is 24-x; this gives us

$\frac{6}{24-x}$

For the time downstream, the distance is 10 and the rate is 24+x; this gives us

$\frac{10}{24+x}$

Together, these give us the equation

$\frac{6}{24-x}=\frac{10}{24+x}$

We cross-multiply to solve this:
6(24+x) = 10(24-x)

Using the distributive property, we have
6*24 + 6*x = 10*24 - 10*x
144+6x = 240-10x

Adding 10x to each side,
144+6x+10x = 240-10x+10x
144+16x = 240

Subtract 144 from each side:
144+16x-144 = 240-144
16x = 96

Divide both sides by 16:
16x/16 = 96/16
x = 6

4 0

3 years ago

Read 2 more answers