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Ainat [17]
3 years ago
13

SOOMEONEEEEE PLEASE HELLLLLLP MEEEEEEEEE just answer these math problems (don't put an answer if you cant do it please because I

checked all the time and I need this so BAAAD just comment for questions and more) :) technically is not homework but I just feel bad for not doing it (and ill marked it brainliest and 15 points if that is fine)

Mathematics
1 answer:
larisa [96]3 years ago
8 0

Answer:

2).X= 3.464 m

3).X= 86.60m

4).X= 51.96 m

5).X= 30 m

6). X=3.193 m

7). X= 126.2 m

8).79.41m = x

9). 14.3km = x

10). 173.21 m= x

Step-by-step explanation:

For question 2

Distance of ladder from the foot

Tan60= 6/x

X= 6/tan 60

X= 3.464 m

For question 3

The height of the wall x is

Sin 60= x/100

X= 100*0.8660

X= 86.60m

Question 4

The distance between tree and tower is x

Tan30 = 30/x

X= 30/tan 30

X= 30/0.5774

X= 51.96 m

Question 5

If TanA= 3/4

And base = 40 m

TanA= x/40

Equating

X/40= 30/40

X= 30 m

Question 6

The length of ladder= x

Cos 20 = 3/x

X= 3/cos20

X=3.193 m

Question 7

Length of the string= x

Sin 31= 65/x

X= 65/sin 31

X= 126.2 m

Question 8

Height of kite= x

Tan ∅ = 15/8

∅= Tan^-1(15/8)

∅=61.93°

Sin∅= x/90

Sin61.93 *90= x

79.41m = x

Question 9

Height above ground= x

Tan 50= x/12

Tan 50 * 12 = x

14.3 km = x

Question 10

Height of balloon above ground= x

Sin60= x/200

Sin 60 *200 = x

173.21 m= x

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Ad libitum [116K]

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2=1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the least common denominator for 2/3 and 3/5
ivolga24 [154]

Answer: 15

Step-by-step explanation: The common denominator for these 2 fractions is simply the least common multiple for the 2 denominators.

To find the least common multiple or <em>lcm</em> of 3 and 5, we begin by listing the first few multiples of each number.

<em>Multiples of 3</em>

1 x 3 = 3

2 x 3 = 6

3 x 3 = 9

4 x 3 = 12

5 x 3 = 15

We skipped 0 x 3 because our lcm can't be 0.

Next we list the multiples of 5.

<em>Multiples of 5</em>

1 x 5 = 5

2 x 5 = 10

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Notice that 15 appears in both lists so

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4 0
3 years ago
Find the half life of a substance which decays according to the function A(t)=600e^-0.05t, where t is time in days. Round to the
Pavel [41]

Answer:

14 days

Step-by-step explanation:

The half life of a substance is the time required until the object has only half of the inicial mass.

So, to find the inicial mass of the object, we use t = 0 in the equation A(t):

A(0) = 600*e^0 = 600

Half of this mass is 300, so we can use A(t) = 300 and then find the time:

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e^-0.05t = 0.5

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8 0
4 years ago
I need serious help to figure this out
riadik2000 [5.3K]
EAC is 48
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3 0
3 years ago
-2/3- (-3/4)<br><br> Simplify if needed <br> Brainliest <br><br> Also, 5/6+5/12
bazaltina [42]

Answer:

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

Step-by-step explanation:

Given

-\frac{2}{3} - (-\frac{3}{4})

Required

Solve:

-\frac{2}{3} - (-\frac{3}{4})

Open bracket

-\frac{2}{3} - (-\frac{3}{4}) = -\frac{2}{3} +\frac{3}{4}

Take LCM

-\frac{2}{3} - (-\frac{3}{4}) = \frac{-8+9}{12}

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12}

Take LCM

\frac{5}{6} + \frac{5}{12} = \frac{10+5}{12}

\frac{5}{6} + \frac{5}{12} = \frac{15}{12}

Divide by 3/3

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

4 0
3 years ago
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