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Phoenix [80]
1 year ago
3

Evaluate the expression when b= 6 and x = -5. -b+ 2x

Mathematics
1 answer:
victus00 [196]1 year ago
4 0

Given the below expression;

-b+2x

Evaluating the expression when b = 6 and x = -5, we'll have;

\begin{gathered} -(6)+2(-5) \\ -6-10 \\ -16 \end{gathered}

Therefore, when b = 6 and x = -5, the expression will be -16.

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How do you solve this system equation using elimination
laiz [17]
3x +y = 23 this is the same as y=23-3x
3x - 2y = 8 this is the same as 3x/2-8/2=y, which gives you; y=1,5x-4
so;y=23-3xy=1,5x-4
y=y
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<span>y=5</span>
3 0
4 years ago
Read 2 more answers
3x+2y=2<br> Y=x-9<br><br> A) (4,-5)<br> B) (4,13)<br> C) (-5,4) <br> D) (20,11)
BlackZzzverrR [31]
Y = X - 9
so 3X +2Y = 2
will be 3X +2×(X-9) = 2
3X + 2X -18 = 2
5X = 2 + 18
5X = 20
X = 4
Y = X - 9
Y = 4-9
Y = -5
the answer will be A) (4,-5)
please mark me as brainlest
4 0
3 years ago
A hypothesis will be used to test that a population mean equals 10 against the alternative that the population mean is more than
PilotLPTM [1.2K]

Answer:

A) 2.58

B) 1.96

C) 1.65

Step-by-step explanation:

A hypothesis used to test that

H_o : \mu  = 10

against the alternatives H1 : \mu not equal to 10

if null hypothesis is true, then distribution of test statics follow

Zo = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}

for two sided alternatives  hypothesis ( H1: \mu \neq 7), then P value is

P = 2[1- \phi(\left | Zc \right |)]                          (1)

a)significance level  \alpha = 0.01

from 1 eq we get

\pi (\left | Zc \right |) = P(Zo

Therefore  \left | Zc \right | = 2.58    FROM Z TABLE

B) significance level  \alpha = 0.05

from 1st equation we get

\pi (\left | Zc \right |) = P(Zo < \left | Zc \right |) = 1 - \frac{0.05}{2}  = 0.975

Therefore  \left | Zc \right | = 1.96    FROM Z TABLE

C) significance level  \alpha = 0.10

from 1 eq we get

\pi (\left | Zc \right |) = P(Zo

Therefore  \left | Zc \right | = 1.65    FROM Z TABLE

3 0
4 years ago
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