The scale factor 0.05 refers to length, so for area the scale factor is 0.05²=0.0025.
We then multiply: 220 ft²*0.0025=0.55 ft² (choice A)
Answer:
see the explanation
Step-by-step explanation:
we have
<em>Felicia</em>
![-5(3x+2)+10x](https://tex.z-dn.net/?f=-5%283x%2B2%29%2B10x)
Apply distributive property
![-5(3x)-5(2)+10x](https://tex.z-dn.net/?f=-5%283x%29-5%282%29%2B10x)
![-15x-10+10x](https://tex.z-dn.net/?f=-15x-10%2B10x)
Combine like terms
![-5x-10](https://tex.z-dn.net/?f=-5x-10)
Let
a ----> the missing term with coefficient x in Gregory's expression
b ----> the missing constant term in Gregory's expression
so
![-12-4x+ax+b](https://tex.z-dn.net/?f=-12-4x%2Bax%2Bb)
equate Gregory's expression to Felicia's expression
![-12-4x+ax+b=-5x-10](https://tex.z-dn.net/?f=-12-4x%2Bax%2Bb%3D-5x-10)
so
----->![b=2](https://tex.z-dn.net/?f=b%3D2)
------> ![a=-1](https://tex.z-dn.net/?f=a%3D-1)
so
Gregory's expression is
![-12-4x+2-x](https://tex.z-dn.net/?f=-12-4x%2B2-x)
therefore
The missing terms are 2 and -x
Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
3(6x+2)-18x=12 (y=6x+2, so you plug in 6x+2 into the y in 3y-18x=12)
18x+6-18x=12 (Then you distribute the 3 to the 6x and to the 2)
6=12 (Combine like terms 18x-18x)
There is no solution. Hope this helps and makes sense.
What do you mean this question dosent make any sence