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Marrrta [24]
1 year ago
12

Apples cost $3.60 for 3 lb. At that rate, how many pounds of apples can you buy for $8.40?

Mathematics
1 answer:
irinina [24]1 year ago
6 0

Apples cost $3.60 for 3 pounds . The rate can be calculated as follows

\begin{gathered} 3\text{ pounds = \$3.60} \\ 1\text{ pounds = ?} \\ \text{rate = }\frac{3.60}{3} \\ \text{rate}=\text{ \$1.2 per pound} \end{gathered}

The amount of pounds you can buy for $8.40 can be computed below

\begin{gathered} \text{rate}=\frac{8.40}{\text{pounds}} \\ 1.2=\frac{8.40}{\text{pounds}} \\ weight\text{ in pounds = }\frac{8.40}{1.2} \\ \text{weight in pounds = 7 Ib} \end{gathered}

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Mark has $100,000 to invest. His financial consultant advises him to diversify his investment in three types of bonds: short-ter
galina1969 [7]

Answer:

Short-Term investment: 5000$

Intermediate-Term investment: 65000$

Long-Term investment: 30000$

Step-by-step explanation:

To construct our first equation lets define sort-term bond investment as x, long-term investment as y.

So the equation is:

x*0,04+(100000-x-y)*0,05+y*0,06=5250

From the equation it is found that:

y=25000+x

Instead of y, if we put 25000+x the equation will be as following:

x*0,04+75000*0,05+(25000+x)*0,06=5250

From the equation it is found that:

x=5000

Short-Term investment is 5000$

x+25000=y

Long-Term investment is 30000$

Rest of the money is Intermediate-Term investment 65000$

5 0
3 years ago
Solve for x.<br> 3(3x - 1) + 23 - x) = 0
enot [183]
9x-3+69-3x=0
6x+66=0
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3 0
3 years ago
160 is 120% of what number?
LuckyWell [14K]
120 % = 160

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Find 1 % :
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120% = 160
1% = 160 ÷ 120
1% = 4/3

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Find 100% :
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1% = 4/3
100% = 4/3 x 100
100% = 133 1/3

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Answer: 160 is 120% of 133 1/3
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8 0
3 years ago
Read 2 more answers
Pls help I will mark brainlist if correct !! :))
andreev551 [17]
You add all fruit and times to 3/8 to find strawberries

3 0
3 years ago
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
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