All categories

3 years ago

What is the answer to 5 over6 plus 8over 9

Mathematics

1 answer:

solmaris [256]3 years ago

4 0

Answer:

Exact Form:

31/18

Decimal Form:

1.72222222222222222222222

Mixed Number Form:

1 $\frac{13}{18}$

Step-by-step explanation:

You might be interested in

MP bisects ∠BMS. If m∠BMP = 2x + 9 and m∠BMS = 7x – 3, find the value of m∠PMS

dimulka [17.4K]

Answer:

Step-by-step explanation:

If MP bisects ∠BMS, then the line MP divides <BMS equally;

The adition postulate if therefore true;

<BMP +< PMS = <BMS and <BMP = < PMS

The equation becomes;

<BMP +< BMP= <BMS

2 <BMP = <BMS

2(2x+9) = 7x - 3

4x+18 = 7x-3

collect like terms

4x-7x = -3-18

-3x = -21

x = 21/3

x = 7

Since <BMP = < PMS 2x+9

< PMS = 2(7)+9

< PMS = 14+9

< PMS = 23

Hence the value of < PMS is 23

3 0

3 years ago

A group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are list

Anit [1.1K]

Answer:

Step-by-step explanation:

Given that a group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below.

Data set is as ollows:

70 79 38 63 44 23 62 61 67 50 61 70 94 87 65

$Mean = 62.27Variance =333.35std dev = 18.258std error = 4.714$

H0: mu = 60 sec

Ha: mu not equals 60 sec

Mean diff = 2.27

$Mean = 62.27Variance =333.35std dev = 18.258std error = 4.714$

Test statistic = 2.27/SE =0.4815

p value =0.6376

Since p>0.05, we accept null hypothesis

i.e. there is statistical evidence to say that students are reasonably good at estimating one minute

8 0

3 years ago

I can’t figure out the next smallest non negative solution. Can you please help me?

nlexa [21]

Let w = cos(x)

The given equation turns into -5w^2 + 4w + 1 = 0. Use the quadratic formula to find that the two solutions, in terms of w, are:

w = -1/5 = -0.2
w = 1

The solution w = 1 leads to cos(x) = 1 which then becomes x = 0, x = 2pi, x = 4pi, etc. The general way to write this is x = 2pi*n where n is any integer. These angles are in radian mode.

The solution w = -0.2 leads to cos(x) = -0.2 which becomes x = arccos(-0.2) = 1.77215 approximately assuming your teacher wants the angle in radian mode. Unfortunately, I don't know the exact value of x here. There may not be an exact value, or finding this exact value may be well beyond the scope of this course.

3 0

3 years ago

The sports field at Patton Elementary School is shaped like a rectangle.The field is 72 yards long and 46 yards wide.What is the

svet-max [94.6K]

Answer:

3312 square yards.

Step-by-step explanation:

Given:

The sports field at Patton Elementary School is shaped like a rectangle having:

Length = 72 yards

Breadth = 46 yards

Question asked:

What is the area of the field in square yard ?

Solution:

As here sports field at Patton Elementary School is shaped like a rectangle, thus we will use the formula ;

$Area \ of\ rectangle=length \times breadth$

$=72\ yards\times46\ yards\\=3312\ square\ yards$

Thus, the area of the sports field at Patton Elementary School is 3312 square yards.

7 0

3 years ago

Hm someone plz help me

sashaice [31]

Answer:

I'm pretty sure it's 127°

4 0

3 years ago