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2 years ago

I know this is easy and i should know but im actually stumped on this one

Mathematics

1 answer:

nordsb [41]2 years ago

8 0

For the given triangles:

There are 3 pairs of congruent angles

the triangles can not be proved using the congruent angles

the congruent angles used to prove the similarity of the triangles

So, the answer will be:

For the given triangle, we can not prove they are congruent.

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For the pair of functions, find the indicated sum, difference, product, or quotient. f(x) = 16 - x2; g(x) = 4 - x Find (f + g)(x

Rudik [331]

(16-x²)+(4-x) or (-x²+16)+(-x+4)

Combine like terms

(-x²+20-x) or (-x²-x+20)

7 0

3 years ago

Read 2 more answers

john needed 13.71 feet of wire to fix a lamp he bought 14 half feet of wire how much did he have left ver

motikmotik

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Just subtract the two values:

14.5 - 13.71 = 0.79

He had 0.79 feet of wire left

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0

4 years ago

Read 2 more answers

Is this factorable please help me.

olga2289 [7]

This can be factored into (2t - 9)(t + 7)

7 0

3 years ago

Ells room measures 78 inches by 96 inches Sarah's room measures 66 inches by 108 inches they want to combine their rooms how lar

Tanya [424]

Let’s find the area of Ells room.
78•96
7,488
Let’s find Sarah’s room.
66•108
7,128
Now add their area together.
14,616 inches squared.

5 0

3 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago