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Vikentia [17]
1 year ago
9

I know this is easy and i should know but im actually stumped on this one

Mathematics
1 answer:
nordsb [41]1 year ago
8 0

For the given triangles:

There are 3 pairs of congruent angles

the triangles can not be proved using the congruent angles

the congruent angles used to prove the similarity of the triangles

So, the answer will be:

For the given triangle, we can not prove they are congruent.

You might be interested in
What is 920milimeters as a fraction of 12meters (as a simplified fraction)
svlad2 [7]

Answer:

83,404 results for: What is 920milimeters as a fraction of 12meters (as a simplified fraction)

Step-by-step explanation:

I hope it's help you

6 0
2 years ago
If anyone can help me I will really appreciate!!
astraxan [27]

Answer:

The decimal form of the equation is y = 2.5x + 10

The equivalent fraction form is y = (5/2)x + 10 because 5/2 = 2.5

===========================================================

Explanation:

We can pick any two columns from the table to form the two points needed.

I'll pick the first two columns

(1, 12.5)

(2, 15)

Then apply the slope formula to those points

m = (y2-y1)/(x2-x1)

m = (15-12.5)/(2-1)

m = (2.5)/(1)

m = 2.5

Now use that slope with either point mentioned to find the y intercept b.

y = mx+b

12.5 = 2.5*1 + b

12.5 = 2.5 + b

12.5 - 2.5 = b

10 = b

b = 10

Or

y = mx+b

15 = 2.5*2+b

15 = 5+b

15-5 = b

10 = b

b = 10

We end up with the same b value.

We found that m = 2.5 is the slope and b = 10 is the y intercept

Therefore we go from y = mx+b to y = 2.5x + 10

This is the same as saying y = (5/2)x + 10 since 2.5 = 5/2

3 0
3 years ago
I need to find the area of below who can help please.
nasty-shy [4]

Triangle

Area = 1/2 b * h

Area = 1/2*15 * 9 = 1/2 * 135 = 67.5

Rectangle

Area = b * h

Area = 15 * 4

Area = 60

Trapezoid

Area = (1/2) * (b1 + b2)* h

Area = (1/2) * (15 + 18) * 4

Area = 1/2 * 33 * 4

Area = 66

Total Area

Total Area = 66 + 60 + 67.5 = 193.5 Answer

5 0
3 years ago
) Find the coordinates of the point A' which is the symmetric point
soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point  A(3, 2) with respect to the line 2x + y - 12 = 0.​

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

C( \dfrac{x+3}{2}, \dfrac{y+2}{2})

Also, product of slope will be -1 .( Since, they are parallel )

\dfrac{y-2}{x-3} \times -2  = -1\\\\2y - 4 = x - 3\\\\2y - x = 1

x = 2y - 1

So, C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})

Also, C satisfy given line :

2\times ( \dfrac{2y + 2}{2})  + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}

Also,

x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}

Therefore, the symmetric points isA'(\dfrac{31}{5}, \dfrac{18}{5}) .

7 0
2 years ago
How are expressions and equations different.
jeka57 [31]

Answer:

Equations are composed for many expressions.

Expressions can indicate variables, constants, etc.

Best regards

5 0
3 years ago
Read 2 more answers
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