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3 years ago

"Trust is like paper, once it's crumpled it can't be perfect again" meaning what?

Mathematics

1 answer:

NISA [10]3 years ago

8 0

If you crumble paper it is hard to uncrumble like trust

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Maya is learning to drive, so this weekend she practiced driving 1/2 of a mile with her mother and another 3/4 of a mile with he

vitfil [10]

Step-by-step explanation:

1/2 + 3/4

= 2/4 + 3/4

= 5/4

= 1 and 1/4 miles

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3 years ago

Use the graph to determine the input value for

musickatia [10]

Answer: x=1.5

Step-by-step explanation:

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3 years ago

You have a spinner with the following colors 2 yellow, 4 red, and 2 orange. What is the likelihood of the spinner landing on RED

mrs_skeptik [129]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

Find the measure of Angle R to the nearest tenth. a. 63.8 degrees b. 67.2 degrees c. 70.9 degrees d. 61.5 degrees

Vikki [24]

The complete question in the attached figure

we know that
tan R°=opposite side angle R/adjacent side angle R
opposite side angle R=72 units
adjacent side angle R=25 units
so
tan R°=72/25
R=arc tan (72/25)---------> R=70.85°-------> R=70.9°

the answer is
R=70.9°

8 0

3 years ago