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Leokris [45]
1 year ago
9

4a. Riley is buying things for a holiday party that she is having. She wants to make a cheese and cracker appetizer; every crack

er will have a piece of cheese. If crackers come in sleeves of 24 and cheese slices come in packages of 16, what is the least number of cheese and cracker appetizers can she make, so that every cracker has a piece of cheese arld there are no left overs?4b. How many sleeves of crackers will she need to buy?4c How many cheese slices will she need to buy?
Mathematics
1 answer:
S_A_V [24]1 year ago
8 0

4a.

We can get the least number by taking LCM of 24 and 16.

We list each of the numbers as prime factors and take the mutiplication of each unique prime factor that occurs the greatest number of times.

24 = 2 * 2 * 2 * 3

16 = 2 * 2 * 2 * 2

So,

2 occurs four times

3 occurs 1 times

LCM of 24 and 16 is:

2 * 2 * 2 * 2 * 3 = 48

Least number of cheese and cracker appetizer = 48

4b.

Sleeves are sold in 24.

So, to get 48, she would need to buy:

48/24 = 2 sleeves

4c.

Cheese slices comes in packages of 16. So she needs to buy:

48/16 = 3 packages of cheese

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20%

Step-by-step explanation:

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3 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
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Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

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Answer:

13 to 25

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\frac{13}{25}

Step-by-step explanation:

All of these show the ratio 13/25

Hope this helps!

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3 years ago
Please help this is due in 3 hours!! #17
Westkost [7]

Answer:

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3 years ago
Question:
Genrish500 [490]

Answer:

x=56 and the exterior angle is 116

Step-by-step explanation:

We will call the unknown angle in the triangle y.  Angle y and the angle (2x +4) form a straight line so they make 180 degrees.

y + 2x+4 =180

Solve for y by subtracting 2x+4 from each side.

y + 2x+4 - (2x+4) =180 - (2x+4)

y = 180-2x-4

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-x = -56

Multiply each side by -1

-1*-x = -56*-1

x=56

The exterior angle is 2x+4.  Substitute x=56 into the equation.

2(56)+4

112+4

116


8 0
4 years ago
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