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777dan777 [17]
1 year ago
13

An automotive technician has two job offers. Shop A would pay him a straight salary of $900 per week. Shop B would pay him $25 p

er hour to work flat rate, where hishours would vary according to how many jobs he completes. How many hours would he have to log during a week at Shop B in order to match the salary at Shop A?He would have to log hours during a week at Shop B in order to match the salary at Shop A.Please help

Mathematics
1 answer:
JulsSmile [24]1 year ago
7 0

Given,

The salary for the technician from shop A is $900 per week.

The salary for the technician from shop B is $25 per hour.

The equation for the total pay for shop B is,

\text{Total pay= salary of per hour}\times number\text{ of hour worked}

Taking the total pay as 900. As, to make the shop A and shop B equal.

\begin{gathered} 900=25\times Number\text{ of hour worked} \\ Number\text{ of hour worked}=\frac{900}{25}=36 \end{gathered}

Hence, he would have to log 36 hours during a week at Shop B in order to match the salary at Shop A.

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Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f
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Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that p = \frac{3}{4} = 0.75

Giannis shoots three free throws

This means that n = 3

What is the probability that he succeeds on at least two of them

P(X \geq 2) = P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219

P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438

84.38% probability that he succeeds on at least two of them

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3 years ago
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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<h3>Factor –3y – 18 is:  -3(y + 6)</h3>

<em><u>Solution:</u></em>

Given that we have to factor -3y - 18

Use the distributive property,

a(b + c) = ab + bc

From given,

-3y - 18

Factor out the greatest common factor of 3 and 18

The factors of 3 are: 1, 3

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Then the greatest common factor is 3

Factot out 3 from given expression

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Or else we can rewrite as,

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