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serious [3.7K]
3 years ago
6

What exponential function is best fit for the data table?

Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0

Answer:

Hence, the exponential function that best fits the data is:

f(x)=3\times 2^{x-2}+4  (Option A)

Step-by-step explanation:

We are given a set of values as:

x        f(x)

3        10

4        16

5        28

so we will put the value of x=3 in each of the given options and check which function gives the value 10.

i.e. at x=3 which function f(x)=10.

B)

f(x)=3\times 2^{x-2}-4

when x=3.

f(3)=3\times 2^{3-2}-4\\\\f(3)=3\times 2-4\\\\f(3)=6-4\\\\f(3)=2\neq 10

Hence, option B is incorrect.

C)

f(x)=\dfrac{1}{3}\times 2^{x-2}+4

when x=3

f(3)=\dfrac{1}{3}\times 2^{3-2}+4\\\\f(3)=\dfrac{1}{3}\times 2+4\\\\f(3)=\dfrac{14}{3}\neq 10

Hence, option C is incorrect.

D)

f(x)=\dfrac{1}{3}\times 2^{x-2}-4

when x=3

f(3)=\dfrac{1}{3}\times 2^{3-2}-4\\\\f(3)=\dfrac{1}{3}\times 2-4\\\\f(3)=\dfrac{-10}{3}\neq 10

Hence, option D is incorrect.

A)

f(x)=3\times 2^{x-2}+4

when x=3.

f(3)=3\times 2^{3-2}+4\\\\f(3)=3\times 2+4\\\\f(3)=6+4\\\\f(3)=10

similarly A option holds for other values of x as well.

Hence, option A is correct.

Hence, the exponential function that best fits the data is:

f(x)=3\times 2^{x-2}+4

Sedaia [141]3 years ago
6 0
F(x) = 3(2)^(x − 2)<span> + 4</span>
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Data given

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The characteristic equation method assumes that y(t)=e^{rt}, where "r" is a constant.

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As e^{rt} could never be zero, the term (r²+1) must be zero:

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So we use these derivatives in the differential equation:

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