No it is irrational. Hope that this helped you.
Answer:
u did'nt put any problems?
Step-by-step explanation:
Answer:
The length of the rectangle is 11 inch and its width is 8 inch.
Step-by-step explanation:
Given:
Rectangle
and rectangle
.
Let the width of the rectangle be 'x' inch.
Its length = '(x+3)' inch
Area of the rectangle = 
⇒
= 
Now for rectangle
its width is decreased by 1 inch and length is doubled,the area
will increased by 66 sq-inch.
So,
According to the question.
⇒ Area of rectangle
with width '(x-1)' and length '2(x+3)'='(2x+6)' .
⇒ 
Plugging the values of
in terms of
.
⇒ 
Plugging
=
into the equation.
⇒
⇒ 
⇒ 
⇒ 
Now using quadratic formula we can find the value of 'x'.
Quadratic formula, (x)=
x= -9 and x= 8
Discarding the negative value.
Our width = 'x' = 8 inches.
So the length of the rectangle = 11 inches and width of the rectangle = 8 inches.
Probaility in general is defined as the ratio of positive outcomes over the total number of outcomes.
In the first example, the total outcomes are 16; let us count the positive ones. There are 8 even numbers from 1-16. The prime numbers are 2,3,5,7,11,13. Out of those, only 5 are odd. Hence, in total there are 13 positive outcomes. Thus, the probability is 13/16=81.25%
Let's restrict the problem to the students that studied for the exam; the proportion is 0.57 of the total students. 0.52 of the total students studied and saw an increase in their exam. Hence, the probability that a student who studied saw an increse is 0.52/0.57 (here a positive outcome is the proportion that saw an increase and the total outcomes are all the students that studied). 0.52/0.57=91.22%