Answer:
6x−12x^2
Step-by-step explanation:
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
The x-intercepts are: -0.5 and 2.
