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inn [45]
3 years ago
9

I NEED HELPPP PLEASEEEEEEEEEEEEEE

Mathematics
1 answer:
ELEN [110]3 years ago
8 0
59 I have done this before
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Find the value of x of the circle, and show the work of the equation:
slavikrds [6]
AOD=180 so COD=48
Since point C and D are equidistance to center point(O) OD and OC are congruent.
That also means OCD=ODC.
180-48=OCD+ODC
ODC=OCD
x= 66
8 0
3 years ago
PLEASE SOME ONE HELP ME IM DYING!!!!!
Afina-wow [57]
We know the area of the middle rectangle is 48 (length * width). removing that rectangle leaves us with two semicircles. you can combine those semicircles to be the equivalent of one circle. the area for a circle is r^2 * pi. we know the diameter is 4 because that is where we cut the semicircles. radius is half the diameter, so r is 2. 2^2 is 4, 4* pi is 12.56. add 12.56 (area of semicircles) with 48 (area of rectangle) and we get 60.56
4 0
4 years ago
A rectangle has a perimeter of 54 cm. It has a length of 15 cm. What is its area? *
d1i1m1o1n [39]

the area is 180 cm. to find the perimeter you would do 15+15+14+14 to get 54 cm. So for area you do (l×w) which is 15×14=180.

5 0
3 years ago
131.12 divided by 44
Arte-miy333 [17]
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6 0
4 years ago
Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s
Ierofanga [76]

Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$\beta=10\log\left(\frac{I}{I_0} \right)

where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

5 0
4 years ago
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