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Answer:
The requirement of the question is as below:
How much must Alan deposit on January 1? (Round your final answer to the nearest whole dollar amount.)
What is the interest for the four years? (Round your final answer to the nearest whole dollar amount.)
Alan deposit on January 1 is $ 58,802.39
Interest for four years is $21,197.61
Explanation:
The first is asking for today's worth of the investment,which is the amount to be invested,this can be computed using the present value as shown below:
PV=FV*(1+r)^-n
PV is the present value
FV is the worth of the investment in 4 years from now which is $80,000
r is the rate of return of 8%
n is the number of years of investment which is 4 years
PV=$80,000*(1+8%)^-4
PV=$80,0008(1+0.08)^-4
PV=$80,000*(1.08)^-4
PV =$ 58,802.39
interest for four years=FV-PV
interest for four years=$80,000-$ 58,802.39
=$21,197.61
Answer:
Following is the solution for the given problem.
Explanation:
Best order size, EOQ =√2DS/H
EOQ = √2*4700*60/5
EOQ = 336 units.
D = 4700/300 = 15.66.
σ L= √∑σ²
= √3*(5)² = 8.66.
Reorder point, R = D*L+ z σ L
Reorder point, R = 15.66*3 + 1.282*8.66
Reorder point, R = 58 units.
