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lawyer [7]
1 year ago
14

An enzyme that follows simple michaelis–menten kinetics has an initial reaction velocity of 10 μmol⋅min−1 when the substrate con

centration is five times greater than the km. What is the vmax of this enzyme?.
Biology
1 answer:
svet-max [94.6K]1 year ago
6 0

The Vmax of the enzyme is 12 μmol⋅min−1

We use Michaelis-menten equation,  which is given by;

V=\frac{Vmax(S)}{Km+(S)} \\

Where v is velocity of reaction

Vmax = maximum rate achieved by the system

[S] = concentration of a substrate

K_{m}= Michaelis constant

Given V_{0} = 10umolmin^{-1}

[S] = 5km

Now, we calculate Vmax:

10umolmin^{-1} = \frac{Vmax*(5Km)}{Km+5Km}

Km = 1

10=\frac{5KmVmax}{6Km}

\frac{10*6}{5} =Vmax

Vmax =12 μmol⋅min−1

Learn more about Michaelis-menten kinetics here:

brainly.com/question/15180587

#SPJ4

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