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Xelga [282]
3 years ago
12

A geneticist discovers an obese mouse in his laboratory colony. He breeds this obese mouse with a normal mouse. All the F1 mice

from this cross are normal in size. When he interbreeds two F1 mice, eight of the F2 mice are normal in size and two are obese. The geneticist then intercrosses two of his obese mice, and he finds that all of the progeny from this cross are obese. These results lead the geneticist to conclude that obesity in mice results from a recessive allele. Call this allele O1.
A second geneticist at a different university also discovers an obese mouse in her laboratory colony. She carries out the same crosses as the first geneticist did and obtains the same results. She also concludes that obesity in mice results from a recessive allele. Call this allele O2.

One day the two geneticists meet at a genetics conference, learn of each other's experiments, and decide to exchange mice. They both find that, when they cross two obese mice from the different laboratories, all the offspring are normal; however, when they cross two obese mice from the same laboratory, all the offspring are obese. Select the answer that gives the best explanation for these results.

a. The O1 allele is recessive, but the O2 allele is dominant.
b. The O2 allele is recessive, but the O2 allele is dominant.
c. Both alleles are recessive, but they must be located at different gene loci.
d. Both alleles are dominant, but they must be located at different gene loci
Biology
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

<h2>c. Both alleles are recessive, but they must be located at different gene loci.</h2>

Explanation:

Given:

If  he inbred normal mice and obese mice ,  all the F1 mice  are normal.

F1 and F1 interbred : 8 are normal and 2 are obese.

obese and obese = all are obese.

hence O1 proved as recessive allele.

in second experiment :

O2 is proved as recessive allele.

But when both obese mice of different laboratories are inter-crossed, all the offspring are normal, hence it is proved that Both alleles are recessive, but they must be located at different gene loci.

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Pot A that contained no fertilizer or compost will serve as a control in this experiment.

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Fertilizer may be defined as any chemical or natural substance which is added to the soil with the intention to enhance the soil productivity.

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2 years ago
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ki77a [65]

Answer:the first on is a convergent boundary and the second also looks like a convergent boundary

Explanation:

7 0
3 years ago
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vodomira [7]

Answer:

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3 years ago
The LMand LNalleles at the MN blood-group locus exhibit codominance. Give the expected genotypes and phenotypes and their ratios
Dmitry [639]

Answer:

Please find the expected genotypes and phenotypes of the progenies of each cross below.

Explanation:

In the MN blood-group locus of the gene, alleles LM and LN exhibit codominance i.e one allele is not dominant or recessive to the other, hence, they are both expressed when they occur in a heterozygous state (MN).

Considering the following crosses (find the punnet square attached);

a)LMLM x LMLN - The progeny are LMLM and LMLN in the genotypic ratio 1:1. Phenotypic ratio is Blood type M (1) : blood type MN (1)

b) LNLN x LNLN - The progeny are all LNLN offsprings with a phenotypic and genotypic ratio 4:0. All offsprings will have a blood type N (4)

c) LMLN x LMLN - The progenies are LMLM, LMLN and LNLN in the genotypic ratio 1:2:1 respectively. The phenotypic ratio is Blood type M (1) : L

Blood type MN (2) : Blood type N (1)

d) LMLN x LNLN - The progeny are LMLN and LNLN with genotypic ratio 1:1 and phenotypic ratio blood type MN (1) : blood type N (1)

e) LMLM x LNLN - The progeny are all LMLN offsprings with penotypic ratio blood type MN (4)

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