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1 year ago

Which functions are correctly graphed?

Mathematics

1 answer:

FinnZ [79.3K]1 year ago

7 0

Solution

final answer is.

Choice A, C ,D

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Which ordered pair is the solution to the system of equations?

tiny-mole [99]

Answer:

You can use Gaussian Elimination.

Double both sides of the first equation and add the second equation.

6x + 4y = 8

5x - 4y = 3

---------------

11x = 11

x = 1

5 - 4y = 3

-4y = -2

y = 1/2

Step-by-step explanation:

7 0

4 years ago

Which of the following is a true statement?

Romashka [77]

Florida's climate is a result of high average temperatures, latitude and precipitation. please awnser my question its about the gift shop

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3 years ago

- In the 2016 Summer Olympics, the U.S. team won

kolezko [41]

The answer is 52.

20+52=72

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3 years ago

Can anybody help me

seropon [69]

Since there is no value of x that will ever make this a true statement, the solution to the equation above is “no solution” The solution x = 0 means that the value 0 satisfies the equation, so there is a solution. “No solution” means that there is no value, not even 0, which would satisfy the equation. and Basically just means for all numbers from minus infinity to infinity. We say real x to distinguish from complex numbers. 0. general ebriety. and Basically just means for all numbers from minus infinity to infinity. We say real x to distinguish from complex numbers. 0. general ebriety.

5 0

3 years ago

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$