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2 years ago

Using the following table determine the probability a person tests positive who does not actually have Tuberculosis.

Mathematics

2 answers:

Afina-wow [57]2 years ago

5 0

The probability a person tests positive who does not actually have Tuberculosis is 1/100

<h3>How to determine the probability a person tests positive who does not actually have Tuberculosis?</h3>

The probability is given as:

The probability a person tests positive who does not actually have Tuberculosis.

This is a conditional probability, and it can be calculated using

P = n(Tests positive | Does not have Tuberculosis)/n(Does not have Tuberculosis)

Using the given table of values, we have:

P = 98/9800

Evaluate the quotient

P = 1/100

Hence, the probability a person tests positive who does not actually have Tuberculosis is 1/100

Read more about probability at:

brainly.com/question/25870256

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Lady bird [3.3K]2 years ago

3 0

Using it's concept, the probability a person tests positive who does not actually have Tuberculosis is:

c. 49/148.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are 198 + 98 = 296 people who test positive, which is the number of total outcomes, and of those, 98 do not have the disease, which is the number of desired outcomes. Hence the probability is given by:

p = 98/296 = 49/148.

Which means that option c is correct.

More can be learned about probabilities at brainly.com/question/14398287

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The ratio of two numbers is 8 to 5. The difference in two numbers is 24. What are the numbers?

Varvara68 [4.7K]

Let, the numbers are: 8x, 5x
It is given that, 8x - 5x = 24
3x = 24
x = 24/3
x = 8

So, 8x = 8(8) = 64
also, 5x = 5(8) = 40

In short, Numbers would be 40 and 64

Hope this helps!

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3 years ago

The stadium incurs a number of costs to accommodate fans. If the stadium pays $14,000 for labor, $45,000 for leasing parking spa

julsineya [31]

Check the attached file for the answer.

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3 years ago

PLEASE ANSWER WILL GIVE POINTS!!!!!!!!!!!

iris [78.8K]

Given:

The figure of a right triangle ABC.

To find:

The trigonometric ratios $\sin B, \tan A, \cos B$ .

Solution:

Using Pythagoras theorem,

$Hypotenuse^2=Perpendicular^2+Base^2$

$AB^2=AC^2+BC^2$

$(10)^2=(6)^2+BC^2$

$100-36=BC^2$

$64=BC^2$

Taking square root on both sides.

$\sqrt{64}=BC$

$8=BC$

So, measure of BC is 8 units.

Now,

$\sin \theta=\dfrac{Opposite}{Hypotenuse}$

$\sin B=\dfrac{AC}{AB}$

$\sin B=\dfrac{6}{10}$

$\sin B=\dfrac{3}{5}$

Similarly,

$\tan \theta=\dfrac{Opposite}{Adjacent}$

$\tan A=\dfrac{AC}{BC}$

$\tan A=\dfrac{6}{8}$

$\tan A=\dfrac{3}{4}$

And,

$\cos \theta=\dfrac{Adjacent}{Hypotenuse}$

$\cos B=\dfrac{BC}{AB}$

$\cos B=\dfrac{8}{10}$

$\cos B=\dfrac{4}{5}$

Therefore, the required trigonometric ration are $\sin B=\dfrac{3}{5}, \tan A=\dfrac{3}{4}, \cos B=\dfrac{4}{5}$ .

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3 years ago

A box plot divides the data values into three equal sections. <br><br> true or false

Zinaida [17]

The answer for this is false

3 0

3 years ago

Read 2 more answers

nika2105 [10]

You have to use a calculator for both of the exact values using sin^-1 or Cos^-1 you can then times those together, with the final part the answer is sin 240 as sin(A-B) = sinAcosB-CosASinB

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3 years ago