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Natasha2012 [34]
2 years ago
7

Using the following table determine the probability a person tests positive who does not actually have Tuberculosis.

Mathematics
2 answers:
Afina-wow [57]2 years ago
5 0

The probability a person tests positive who does not actually have Tuberculosis is 1/100

<h3>How to determine the probability a person tests positive who does not actually have Tuberculosis?</h3>

The probability is given as:

The probability a person tests positive who does not actually have Tuberculosis.

This is a conditional probability, and it can be calculated using

P = n(Tests positive | Does not have Tuberculosis)/n(Does not have Tuberculosis)

Using the given table of values, we have:

P = 98/9800

Evaluate the quotient

P = 1/100

Hence, the probability a person tests positive who does not actually have Tuberculosis is 1/100

Read more about probability at:

brainly.com/question/25870256

#SPJ1

Lady bird [3.3K]2 years ago
3 0

Using it's concept, the probability a person tests positive who does not actually have Tuberculosis is:

c. 49/148.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are 198 + 98 = 296 people who test positive, which is the number of total outcomes, and of those, 98 do not have the disease, which is the number of desired outcomes. Hence the probability is given by:

p = 98/296 = 49/148.

Which means that option c is correct.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

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J. J. Redick is an excellent free throw shooter and makes 90% of his free throws (i.e., he has a 90% chance of making a single f
irakobra [83]

Answer:

59.049%

Step-by-step explanation:

J. J. Redick is an excellent free throw shooter and makes 90% of his free throws

P(making one free throw) =90%

Therefore:

P($making 5 consecutive free throws)=P(making 1st) X P(making 2nd) X P(making 3rd)X P(making 4th) X P(making 5th)\\\\=90\%X90\%X90\%X90\%X90\%\\\\=0.9X0.9X0.9X0.9X0.9\\\\=0.59049\\\\=59.049\%

7 0
3 years ago
Which exponential function is represented by the graph?
Anna [14]

Answer:

Step-by-step explanation:

Let's solve this using our formula for exponential functions:

y=a(b)^x where a is the initial value and b is the growth/decay rate. We will fill that equation in with 2 of the coordinates on the graph and come up with the values for both a and b. (0, 3) and (1, 6):

3=a(b)^0. Anything raised to the power of 0 is 1, so that means that

a = 3. We will use that value along with the x and y from the second coordinate to solve for b:

6=3(b)^1. b to the first is just b, so our equation is

6 = 3b and

b = 2.

Our equation then is

y=3(2)^x, the third choice down.

8 0
3 years ago
I NEED HELP <br> PLZZ HELP ASAP<br> i will mark you as brainiest
12345 [234]

Step-by-step explanation:

1+1=78

5 0
3 years ago
You have been asked to design a rectangular box with a square base and an open top. The volume of the box must be 500cm3. Determ
babymother [125]

Answer:

x = 10 cm, y = 5 cm gives a minimum area of 300 cm^2.

Step-by-step explanation:

V= x^2y = 500

Surface area A = x^2 + 4xy.

From the first equation y = 500/x^2

So substituting for y in the equation for the surface area:

A = x^2 + 4x * 500/x^2

A = x^2 + 2000/x

Finding the derivative:

dA/dx = 2x - 2000x^-2

dA/dx = 2x - 2000/x^2

This = 0 for a minimum/maximum value of A, so

2x - 2000/x^2  = 0

2x^3 - 2000 = 0

x^3 = 2000/ 2 = 1000

x = 10

Second derivative is  2 + 4000/x^3

when x = 10  this is positive so x = 10 gives a minimum value of A.

So y =  500/x^2

= 500/100

= 5.

6 0
3 years ago
X + 15 = 28<br> O A. x= 13<br> O B. x = 33<br> O C. x = 43<br> O D. x = 23
Mariana [72]

Answer:

A

Step-by-step explanation:

the answer is

x+15=28

x=28-15

x= 13

7 0
3 years ago
Read 2 more answers
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