Question

Using the following table determine the probability a person tests positive who does not actually have Tuberculosis.

Answer 1

The probability a person tests positive who does not actually have Tuberculosis is 1/100

How to determine the probability a person tests positive who does not actually have Tuberculosis?

The probability is given as:

The probability a person tests positive who does not actually have Tuberculosis.

This is a conditional probability, and it can be calculated using

P = n(Tests positive | Does not have Tuberculosis)/n(Does not have Tuberculosis)

Using the given table of values, we have:

P = 98/9800

Evaluate the quotient

P = 1/100

Hence, the probability a person tests positive who does not actually have Tuberculosis is 1/100

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Answer 2

Using it's concept, the probability a person tests positive who does not actually have Tuberculosis is:

c. 49/148.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there are 198 + 98 = 296 people who test positive, which is the number of total outcomes, and of those, 98 do not have the disease, which is the number of desired outcomes. Hence the probability is given by:

p = 98/296 = 49/148.

Which means that option c is correct.

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