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2 years ago

Using the following table determine the probability a person tests positive who does not actually have Tuberculosis.

Mathematics

2 answers:

Afina-wow [57]2 years ago

5 0

The probability a person tests positive who does not actually have Tuberculosis is 1/100

<h3>How to determine the probability a person tests positive who does not actually have Tuberculosis?</h3>

The probability is given as:

The probability a person tests positive who does not actually have Tuberculosis.

This is a conditional probability, and it can be calculated using

P = n(Tests positive | Does not have Tuberculosis)/n(Does not have Tuberculosis)

Using the given table of values, we have:

P = 98/9800

Evaluate the quotient

P = 1/100

Hence, the probability a person tests positive who does not actually have Tuberculosis is 1/100

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Vlad [161]

<h3>Answer: x = 12</h3>

Explanation:

The two angles shown are vertical angles. This occurs whenever you have an X shape like this, and whenever the angles are opposite one another. Vertical angles are always congruent.

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3 years ago

I need help! I'm *so* confused! I will mark Brainliest

Naddik [55]

Answer:

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Step-by-step explanation:

2 days ago, Paulo's commute time was halfway between his commute times 8 and 9 days ago.

8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.

9 days ago means that x-coordinate -9 represents this day. Count 9 units to the left and find that when x = -9, y = 18 minutes.

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$y=\dfrac{24+18}{2}=\dfrac{42}{2}=21,$

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3 years ago

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liberstina [14]

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3 years ago

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matrenka [14]

Answer:

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3 years ago

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