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vazorg [7]
1 year ago
15

8/3= 19/6n - 1/2n I NEED HELP

Mathematics
1 answer:
pav-90 [236]1 year ago
8 0

Answer:

n = 1

Step-by-step explanation:

\frac{8}{3} = \frac{19}{6} n - \frac{1}{2} n

multiply through by 6 ( the LCM of 3, 6 and 2 ) to clear the fractions

16 = 19n - 3n

16 = 16n ( divide both sides by 16 )

1 = n

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Step-by-step explanation:

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(5x - 4x) + 5

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A coffee machine dispenses normally distributed amounts of coffee with a mean of 12 ounces and a standard deviation of 0.2 ounce
NemiM [27]

Answer:

0.9332 = 93.32% probability that the mean of the sample will be less than 12.1 ounces.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 12 ounces and a standard deviation of 0.2 ounces.

This means that \mu = 12, \sigma = 0.2

Sample of 9:

This means that n = 9, s = \frac{0.2}{\sqrt{9}}

Find the probability that the mean of the sample will be less than 12.1 ounces.

This is the pvalue of Z when X = 12.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{12.1 - 12}{\frac{0.2}{\sqrt{9}}}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

0.9332 = 93.32% probability that the mean of the sample will be less than 12.1 ounces.

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3 years ago
How many four-letter codes can be made if no letter can be used twice?
Y_Kistochka [10]

Answer:4 ways to make a code of 4 letters. 6C4=15, 4!=24, and 15×24=360

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Step-by-step explanation:

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