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2 years ago

7

Need boys to add to a study group chat 9-12 grade plzzzz I already Have other students in it need more that go to connections/co

nnexus academy or GACA

1 answer:

Elenna [48]2 years ago

5 0

Answer:

So do the people who want to study with you give their number? If so, then I can't come cause I am a girl.

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Use the point-slope form, y - y1 = m(x - x1), to find the linear equation of a line that passes through the points

Andreyy89

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2 years ago

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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

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Step-by-step explanation:

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2 years ago

What are the values of the trigonometric ratios for this triangle?

Norma-Jean [14]

We know that
in the right triangle

<span>sinθ=opposite side/hypotenuse
</span><span>cosθ=adjacent side/hypotenuse
</span><span>tanθ=opposite side/adjacent side

in this problem
opposite side angle </span>θ=8
adjacent side angle <span>θ=15
hypotenuse=17
so

</span>sinθ=8/17
cosθ=15/17
tanθ=8/15

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2 years ago