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Murrr4er [49]
1 year ago
13

Write the solution using interval notation: -8 < 2x - 4 < 10

Mathematics
1 answer:
saul85 [17]1 year ago
7 0

Answer:(-2,7)

Step-by-step explanation:

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Is .634 rational number
Ksivusya [100]
Yes 0.634 is a rational number.
Rational numbers are those numbers that can be still expressed in standard form or in fraction form and vice-versa. Unlike irrational numbers that are opposed to the definition of rational numbers. These values include pi, square root of two and etc. These values are impossible to fractionize. To better illustrate this circumstance.

We can have calculate a number that will have a quotient of 0.634 or a fraction that is equal to the given value. <span><span>
1. </span><span> 634/1000 = 0.634</span></span>
<span><span>2. </span><span> 317/500 = 0.634 </span></span>



3 0
3 years ago
Classify the following triangle. Check all that apply. A. Scalene B. Right C. Acute D. Equilateral E. Obtuse F. Isosceles ​
Sati [7]

Answer:

E and F

Step-by-step explanation:

The triangle given has two equal sides, and an obtuse angle that is more than 90° that measures 120°. The other two angles are of equal measure since their opposite sides are of the same length. Thus, this implies that it is an isosceles triangle because it has two equal base angles and two equal sides. It also implies that it is an obtuse triangle since one of it's angles is more than 90°.

3 0
3 years ago
Read 2 more answers
Answer al 4 question and I’ll give your Brainly
miv72 [106K]

Answer:

C-C-B-D

Step-by-step explanation:

Hope this helps and look out for people trying to take your points!

6 0
2 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
2 years ago
X + 12 = 7<br> What does x equal?
makvit [3.9K]

Answer:

-5

Step-by-step explanation:

12-5=7

7 0
2 years ago
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