<em>Greetings from Brasil...</em>
First degree equation. The variables are in the 1st member and the numbers in the 2nd member.
X + 6 - 2X = X - 24
X - 2X - X = - 24 - 6
- 2X = - 30
<h2>X = 15</h2>
9514 1404 393
Answer:
∠CAB = 28°
∠DAC = 64°
Step-by-step explanation:
What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.
<u>Left</u>
Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...
x + x + ∠AEB = 180°
2x = 180° -124° = 56°
x = 28°
The measure of angle CAB is 28°.
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<u>Right</u>
Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.
∠BCA = ∠DAC = 64°
The measure of angle DAC is 64°.
(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)
Answer:
60 degrees, 55 degrees, and 50 degrees respectively
Step-by-step explanation:
Equation: m<1+m<2+m<3=180
1. 40+80+x=180 Subtract 120(because 40+80=120)
x=60
2. 50+75+x=180 subtract 125 (50+75=125)
x=55
3. 50+80+x=180 subtract 130 (50+80=130)
x=50
