Answer:
Cherry Jalopies, Inc.:
mean = (0.22 + 0.11 - 0.04 + 0.06 + 0.09) / 5 = 0.52 / 5 = 0.104
variance = [(0.22 - 0.104)² + (0.11 - 0.104)² + (-0.04 - 0.104)² + (0.06 - 0.104)² + (0.09 - 0.104)²] / 5 = (0.013456 + 0.000036 + 0.020736 + 0.001936 + 0.000196) / 5 = 0.007272
standard deviation = √0.007272 = 0.085276 = 8.53%
Straw Construction Company:
mean = (0.16 + 0.23 - 0.01 + 0.01 + 0.17) / 5 = 0.56 / 5 = 0.112
variance = [(0.16 - 0.112)² + (0.23 - 0.112)² + (-0.01 - 0.112)² + (0.01 - 0.112)² + (0.17 - 0.112)²] / 5 = (0.002304 + 0.013924 + 0.014884 + 0.010404 + 0.003364) / 5 = 0.008976
standard deviation = √0.008976 = 0.09474 = 9.47%
Answer:
B. Both are subtracted from purchases.
Answer:
The financial statement provides the "raw materials" with which the financial performance of an organisation may be analysed.
The financials ratios not only monitor financial performance, but it also speaks to the quality of performance and serves as a basis to compare one period against the other.
The cashflows help to create a picture of the project's liquidity in each of the forecasted periods.
The Income statement helps to gauge the quality of the earnings per period and the balance sheet shows the economic position of the firm at the time under observation.
Cheers!
Answer:
$26.52.
Explanation:
We use the MM Proposition I formula as follows:
VL = VU + (Tc * D) ....................................................... (1)
Where;
VL = Value of a levered firm, i.e. X = ?
VU = Value of an unlevered firm, i.e. Y = $24
Tc = Tax rate = 21%
D = value of debt = $12
Note: The US 2020 corporate tax rate is used as the tax rate since no tax rate is given in the question.
Substituting the values into equation (1), we have:
VL = $24 + (21% * $12) = $24 + $2.52 = $26.52.
Therefore, According to MM Proposition I, the stock price for Firm X is closest to $26.52.
Answer:
The correct option is (B) $365,530.
Explanation:
In this problem we need to determine the future value, i.e. the amount at the retirement age.
The formula to commute the future value is:
![\\ FV=A[\frac{(1+r)^{n}-1}{r}]](https://tex.z-dn.net/?f=%5C%5C%20FV%3DA%5B%5Cfrac%7B%281%2Br%29%5E%7Bn%7D-1%7D%7Br%7D%5D)
Here,
A = annual investment = $5,000
r = interest rate = 8%
n = number of periods = 25
The future value is:
![\\ FV=A[\frac{(1+r)^{n}-1}{r}]\\=5000\times[\frac{(1+0.08)^{25}-1}{0.08}]\\=365529.699\\\approx365530](https://tex.z-dn.net/?f=%5C%5C%20FV%3DA%5B%5Cfrac%7B%281%2Br%29%5E%7Bn%7D-1%7D%7Br%7D%5D%5C%5C%3D5000%5Ctimes%5B%5Cfrac%7B%281%2B0.08%29%5E%7B25%7D-1%7D%7B0.08%7D%5D%5C%5C%3D365529.699%5C%5C%5Capprox365530)
Thus, the amount of money the engineer will have in the account at retirement is $365,530.