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1 year ago

Which side lengths form an obtuse triangle? 0 28, 96, 100 O 40, 75, 85 O 17, 18, 19 O 2, 5,8 O 4, 5, 6

Mathematics

1 answer:

Eddi Din [679]1 year ago

6 0

Solution

For this case in order to have an obtuse angle we need to satisfy this:

$c^2>a^2+b^2$

And we can verify that:

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Iteru [2.4K]

Answer:

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Step-by-step explanation:

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Answer:

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3 years ago

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So what you do is
make into ax^2+bx+c=0 form

add-9/2 to both sides
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ax^2+bx+c=0
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a=1
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subsitute
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x= $\frac{2+/- \sqrt{4-(36/2)} }{2}$
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x= $\frac{2+/- \sqrt{-14} }{2}$
x= $\frac{2+/- \sqrt{-14} }{2}$
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mixas84 [53]

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