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5 months ago

Which side lengths form an obtuse triangle? 0 28, 96, 100 O 40, 75, 85 O 17, 18, 19 O 2, 5,8 O 4, 5, 6

Mathematics

1 answer:

Eddi Din [679]5 months ago

6 0

Solution

For this case in order to have an obtuse angle we need to satisfy this:

$c^2>a^2+b^2$

And we can verify that:

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The ________ of two events X and Y is another event that consists of the sample space outcomes belonging to either event X or ev

sineoko [7]

Answer: Union

i hope its not to late, and please mark me brainlest.

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2 years ago

The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)

sveticcg [70]

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
If x and y coordinates are positive, then the angle lies in the 1st quadrant
If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
If x and y coordinates are negative, then the angle lies in the 3rd quadrant
If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point $(\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})$

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = $\frac{-\sqrt{2} }{2}$

∴ cosФ = $\frac{-\sqrt{2} }{2}$

∵ y-coordinate = $\frac{\sqrt{2} }{2}$

∴ sinФ = $\frac{\sqrt{2} }{2}$

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = $\frac{-\sqrt{2} }{2}$ ÷ $\frac{\sqrt{2} }{2}$

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

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2 years ago

Read 2 more answers

A sporting goods manager was selling a ski set for a certain price. The manager offered the markdowns shown on the right, making

ra1l [238]

Answer:

The original selling price would be $ 515.87 ( approx )

Step-by-step explanation:

Consider the complete question is :

"A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns shown, making the one-day sale price of the ski set $325. Find the original selling price of the ski set. It was marked down 10% and 30%"

Suppose x be the original selling price ( in dollars ),

After marking down 10%,

New selling price = x - 10% of x = x - 0.1x = 0.9x

Again after marking down 30%,

Final selling price = 0.9x - 30% of 0.9x

= 0.9x - 0.3 × 0.9x

= 0.9x - 0.27x

= 0.63x

According to the question,

0.63x = 325

$\implies x =\frac{325}{0.63}=\$ 515.87$