Answer: The mid-point of AC easy to calculate.
It is at ((5+3)/2,(5−1)/2)=(4,2) .
What you really asked was the coordinates of the point 3/4 of the way from A to C, and the calculation is very similar. I think of it as giving a “weighting” to the nearest point. So in this case we give a weighting of 3 to point C and 1 to point A.
Then =((5+3∗3)/4,(5−1∗3)/4)
So =(3½,½) .
CHECK:
Distance
2=(5−3½)2+(5−½)2
=(3/2)2+(9/2)2=9/4+81/4
=90/4
So the distance =310‾‾‾√/2
And the distance
2=(3½−3)2+(½+1)2
=1/4+9/4=10/4
And so the distance BC is 10‾‾‾√/2 which is indeed one third of the distance AB.
Step-by-step explanation:
She could arrange them into 6 tens and 3 ones
Answer:
I would choose f(x)= 3|x-1|
Step-by-step explanation: These are the point on the graph.
(X,Y)
-1,6
0,3
1,0
2,3
3,6
Step-by-step explanation:
for any matrix multiplication number of columns of first matrix should be equal to number of rows of second matrix.
For AB
A has 3 columns and B has 3 rows so it matches . Hence can be multiplied.
For BA
B has 2 columns and A has 2 rows it also matches so can be multiplied
Is the <span>≤ symbol with the fraction x over 12+3 or is it on the side? If it is on the side ex;
x
____ </span>≤7<span>
12+3
x should equal 105 I believe.
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