<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
You get the middle of all the data while looking at the median of a data set!
I hope this helped! Mark me Brainliest! :) -Raven❤️
-5, 5 there u go cuhhhhhhhhh
Answer:
Step-by-step explanation:
Change mixed fraction to improper fraction. Then reduce to lowest term if possible.
6 1/4 x 3 3/5 = 25/4 * 18/5 = 25* 18 /4*5
= 5 * 18 / 4 {giving by 5th table}
= 5* 9 /2 { giving by 2nd tables}
= 45/2
Answer:
step 2:do subtraction in the parentheses
Step 3: distribute
Step 4: add
Step-by-step explanation: